Question

我希望将字词放在字符串的左侧和右侧。例如，如果整个字符串是：

"Programming is my passion"

我想提取"is"左侧和右侧的字词："Programming"和"my"。

Answer 1

\b(\w+) is (\w+)\b

现在参加比赛的第1组和第2组。

sentence = 'Programming is my passion'
word     = 'is'
matches  = sentence.match(/\b(\w+) #{word} (\w+)\b/)

matches[1] # => "Programming"
matches[2] # => "my"

这个想法是：

\b - 字边界
(\w+) - 包含在编号组中的尽可能多的单词字符

Answer 2

这是一个解决方案;

str = "Programming is my passion"
word = "is"
words = str.split(/\W/)
index = words.index(word)
before, after = words[index-1], words[index+1] if index > 0
p before 
#=> "Programming"
p after
#=> "my"

Answer 3

您可以使用以下内容：

\b(\w+)\b\s+is\s+\b(\w+)\b
            ^^

Answer 4

您也可以使用此正则表达式：

(\S+)\s+is\s+(\S+)

DEMO：http://rubular.com/r/rAtgGuh7Oh

Answer 5

带变量：

string = 'Programming is my passion'

matchers = string.match(/(?<before>\w+)?\s?is\s?(?<after>\w*)?/)

matchers[:before] # "Programming"
matchers[:after] # "my"

string = 'Programmingismy passion'
# same tesults

http://rubular.com/r/MvUFf9WVF7

Answer 6

没有正则表达式但使用each_cons()的解决方案。

str = "Programming is my passion"

def neighbors(s, w)
  s.split(/\W/)
   .each_cons(3)
   .find   { |_,e,_| e == w }
   .reject { |e| e == w }
end

before, after = neighbors(str, 'is')

Answer 7

def neighbours str, pattern
  str.scan(/(\S*)\s+#{pattern}\s+(\S*)/).flatten
end

neighbours 'Programming is my passion', 'is'
#⇒ ["Programming", "my"]

查找字符串左侧和右侧的单词

7 个答案: