Question

我有两个表tabData和tabDataDetail。我希望来自Parent-Table（tabData）的所有idData（PK）在Child-Table（tabDataDetail，FK是fiData）中具有仅行，并且：

fiActionCode = 11 或
fiactionCode = 11和fiActionCode = 34

任何其他组合无效。如何获得它们？

我尝试过没有成功的事情（很慢并且还提供了仅 fiActioncode 34的行）：

alt text http://www.bilder-hochladen.net/files/4709-l0.jpg

谢谢你的时间。

编辑：感谢大家的回答。现在我很遗憾没有足够的时间来检查哪一个是最好的还是有效的。我将第一个工作标记为答案。

EDIT2：我认为明确的答案确实是最有效和最紧凑的解决方案。

EDIT3：Codesleuth的答案很有趣，因为它只返回行而不是只有一个fiActionCode = 11。很难看到，因为它的唯一真正的20个tabDataDetail-rows总共41524189行有两个。无论如何，这不是我所要求的100％，而是我正在寻找的东西。

Answer 1

Select ...
From tabData As T1
Where Exists    (
                Select 1
                From tabDataDetail As TDD1
                Where TDD1.fiData = T1.idData
                    And TDD1.fiactionCode = 11
                )
    And Not Exists    (
                      Select 1
                      From tabDataDetail As TDD1
                      Where TDD1.fiData = T1.idData
                          And TDD1.fiactionCode Not In(11,34)
                    )

要扩展我的逻辑，首先检查（更正）是为了确保存在fiActionCode = 11的行。第二项检查首先定义我们不想要的行集。除了fiActionCode = 11或34之外，我们不需要任何其他内容。因为这是我们不想要的项目集，我们会搜索该集合中不存在的任何内容。

Answer 2

<强>推理

LEFT OUTER JOIN排除ID不同于11或34
HAVING排除仅有34
剩余记录（应该）满足所有约束

测试数据

DECLARE @tabData TABLE (idData INTEGER)
DECLARE @tabDataDetail TABLE (fiData INTEGER, fiActionCode INTEGER)

INSERT INTO @tabData VALUES (1)
INSERT INTO @tabData VALUES (2)
INSERT INTO @tabData VALUES (3)
INSERT INTO @tabData VALUES (4)
INSERT INTO @tabData VALUES (5)

/* Only idData 1 & 2 should be returned */
INSERT INTO @tabDataDetail VALUES (1, 11)
INSERT INTO @tabDataDetail VALUES (2, 11)
INSERT INTO @tabDataDetail VALUES (2, 34)
INSERT INTO @tabDataDetail VALUES (3, 99)
INSERT INTO @tabDataDetail VALUES (4, 11)
INSERT INTO @tabDataDetail VALUES (4, 99)
INSERT INTO @tabDataDetail VALUES (5, 34)

<强>查询

SELECT  *
FROM    @tabData d
        INNER JOIN @tabDataDetail dd ON dd.fiData = d.idData
        INNER JOIN (
          SELECT  idData
          FROM    @tabData d
                  INNER JOIN @tabDataDetail dd ON dd.fiData = d.idData
                  LEFT OUTER JOIN (
                    SELECT  fiData
                    FROM    @tabDataDetail
                    WHERE   fiActionCode NOT IN (11, 34)
                  ) exclude ON exclude.fiData = d.idData
          WHERE   exclude.fiData IS NULL                
          GROUP BY
                  idData
          HAVING  MIN(fiActionCode) = 11        
        ) include ON include.idData = d.idData

Answer 3

编辑：Apols - 我明白了你对子行的意思。这不是特别有效。还要感谢列文的数据。

SELECT idData FROM
tabData td
WHERE EXISTS 
(
    SELECT 1 
        FROM tabDataDetail tdd 
        WHERE tdd.fiData = td.idData AND fiActionCode = 11
 )
AND NOT EXISTS
(
    SELECT 1 
        FROM tabDataDetail tdd 
        WHERE tdd.fiData = td.idData AND fiActionCode <> 11
 )
UNION
SELECT idData 
    FROM tabData td
    WHERE EXISTS 
    (
        SELECT 1 
            FROM tabDataDetail tdd 
            WHERE tdd.fiData = td.idData AND fiActionCode = 11
     )
    AND EXISTS
    (
        SELECT 1 
            FROM tabDataDetail tdd 
            WHERE tdd.fiData = td.idData AND fiActionCode = 34
     )
AND NOT EXISTS
(
    SELECT 1 
        FROM tabDataDetail tdd 
        WHERE tdd.fiData = td.idData AND fiActionCode NOT IN (11, 34)
 )

Answer 4

根据对其他答案的评论中的澄清编辑我的答案。

select td.idData
 from tabData td
  left join tabDataDetail tdd
   on td.idData = tdd.fiData
    and tdd.fiActionCode = 11
  left join tabDataDetail tdd2
   on td.idData = tdd2.fiData
    and tdd2.fiActionCode = 34
  left join tabDataDetail tdd3
   on td.idData = tdd3.fiData
    and tdd3.fiActionCode not in (11,34)
 where (tdd.fiData is not null
  or (tdd.fiData is not null and tdd2.fiData is not null))
  and tdd3.fiData is null
 group by td.idData

Answer 5

感谢@ Lieven对数据代码进行测试：

DECLARE @tabData TABLE (idData INTEGER)
DECLARE @tabDataDetail TABLE (idDataDetail int IDENTITY(1,1),
    fiData INTEGER, fiActionCode INTEGER)

INSERT INTO @tabData VALUES (1)
INSERT INTO @tabData VALUES (2)
INSERT INTO @tabData VALUES (3)
INSERT INTO @tabData VALUES (4)
INSERT INTO @tabData VALUES (5)

/* Only idData 1 & 2 should be returned */
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (1, 11)
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (2, 11)
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (2, 34)
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (3, 99)
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (4, 11)
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (4, 99)
INSERT INTO @tabDataDetail (fiData,fiActionCode) VALUES (5, 34)

查询：

SELECT  td.idData
FROM    @tabData td
        INNER JOIN @tabDataDetail tdd ON td.idData = tdd.fiData
WHERE   tdd.fiActionCode = 11 -- check 11 exists
        AND NOT EXISTS ( SELECT * FROM @tabDataDetail WHERE fiData = td.idData
                          AND idDataDetail <> tdd.idDataDetail )
            -- ensures *only* 11 exists (0 results from subquery)
UNION
SELECT  td.idData
FROM    @tabData td
        INNER JOIN @tabDataDetail tdd1 ON td.idData = tdd1.fiData
        INNER JOIN @tabDataDetail tdd2 ON td.idData = tdd2.fiData
WHERE   tdd1.fiActionCode = 11 -- check 11 exists
        AND tdd2.fiActionCode = 34 -- check 34 exists

返回：

idData
-----------
1
2

(2 row(s) affected)

这里只有一个子查询（而且它是一个COUNT而不是一个非常慢的NOT EXISTS）这会创建一个非常简洁的执行计划，如果你遇到速度问题，应该会有所帮助。 / p>

Answer 6

这是通过我认为的数据传递它。

这取决于数据分布是否优于进行2次单独查找。

WITH matches AS
(
SELECT fiData
FROM tabDataDetail 
GROUP BY fiData
HAVING COUNT(CASE WHEN fiactionCode = 11 THEN 1 END) > 0
AND COUNT(CASE WHEN fiactionCode NOT IN (11,34) THEN 1 END) = 0
)
SELECT ...
FROM idData i
JOIN matches m
ON  m.fiData = i.idData

SQL-Query：Subtable中的EXISTS

6 个答案: