Question

假设我有一个名为result的子表。

SELECT school, grade 
  FROM (SELECT school, grade 
          FROM simulated_records 
         LIMIT 10) as result

我如何更新此子表的列？我试过了：

UPDATE result 
   SET grade = 'A'

...但我收到了错误。

Answer 1

sub *选择*是临时的，它们无法更新。听起来你想要一个temporary table

CREATE TEMP TABLE temp_grades AS
SELECT school, grade FROM simulated_records;
UPDATE temp_grades SET grade = 'A';

编辑：你的评论：

UPDATE simulated_records
FROM (SELECT id FROM simulated_records WHERE school='Yale' LIMIT 10) AS result
SET grade='A'
WHERE id = result.id
RETURNING *;

以上使用子选择

的UPDATE FROM表操作

编辑2：第二评论：

假设你没有拼写错误，也许你有旧版本。还有另一种方法可以提供更好的支持：

UPDATE simulated_records SET grade = 'A' WHERE id IN
  (SELECT id FROM simulated_records WHERE school = 'Yale' LIMIT 10);

更新子表

1 个答案: