Question

我一直在设置无效的语法错误 forguessesTaken in range(1, 7):行。 Python一直说:是无效的语法。这真让我抓狂。有人可以帮忙吗？

# this is a guess the number game.
import random
secretnumber = random.randint(1,20)
print('I am thinking of a number between 1 and 20.')

# ask the player to guess 6 times.

forguessesTaken in range(1, 7):
    print('take a guess.')
    guess = int(input())

    if guess < secretnumber:
        print('your guess is too low.')
        elif guess > secretnumber:
            print('your guess is too high.')
            else:
                break # this condition is the corret guess!

            if guess == secret number:
                print('good job! You guessed my number in ' + str(guessestaken) + 'guesses!')
                else:
                    print('nope. the number i was thinking of was ' + str(secretnumber))

Answer 1

python中没有名为forguessesTaken的关键字。也许你忘记在for和guessesTaken之间留出空格。在它们之间留一个空格：

for guessesTaken in range(1,7):
    // remaining code...

Answer 2

请改用此代码：

for guessesTaken in range(1, 8):
    if guessesTaken == 8:
        print('Nope. The number I was thinking of was', secretnumber)
        break
    guess = int(input('Take a guess: '))

    if guess < secretnumber:
        print('Your guess is too low.')
    elif guess > secretnumber:
        print('Your guess is too high.')
    else:
        print('Good job! You guessed my number in', guessesTaken, 'guesses!')
        break

简单的Python代码无效的语法

2 个答案: