Question

我在使用这段代码时遇到了麻烦。

print("The Overall Winner is,", sorted(data, key=lambda(x,y): sum(n[1] for n in y), reverse=True),sum(event[1] for event in event_data))

这是说语法无效，我不知道它有什么问题。

这是该计划的其余部分

def main():
print("Welcome!\n")

n_events = get_number_of_events()
events_names = get_events_names(n_events)
print()
data = get_data(events_names)
print()
for house_name, event_data in data:
    print ("House " + house_name)

    for event_name, score in event_data:
        # note the use of tuple unpacking 
        print ("\tEvent: %s Score: %i" % (event_name, score))

print("The Overall Winner is,", sorted(data, key=lambda(x,y): sum(n[1] for n in y), reverse=True),sum(event[1] for event in event_data))

感谢您提供任何帮助。

编辑：

整个计划。

LOWER_BOUND = 0
UPPER_BOUND = 100

def get_score(house_name, event_name):
score = -1
while score < LOWER_BOUND or score > UPPER_BOUND:
    try:
        score = int(input("Please enter score for %s in the event %s:" % (house_name, event_name)))
        if score < LOWER_BOUND :
            print ("Score is too low, minimum score is %i.\nPlease try again." % min_score)
        if score > UPPER_BOUND:
            print ("Score is too high, maximum score is %i\nPlease try again." % max_score)
    except ValueError:
        print("Invalid Input please enter an integer. Thanks")
return score

def get_number_of_events():
print("Please enter the number of events there is.")
while True:
    try:
        n_events = int(input(">>"))
    except ValueError:
        print("Enter only a number, Thanks.")
    if n_events > 100:
        print("WOW, that's a lot of events, please be reasonable. Thanks.")
    elif n_events < 1:
        print ("That's too few events! Try Again.")
    else:
        break
return n_events

def get_events_names(n_events):
print ("Please enter the events names")
events = []
for n in range(1, n_events + 1):
    event_name = input("Event %i name: " % n)
    events.append(event_name)
return events

def get_data(events):
data = []
while True:
    house_name = input("Please enter house names <<<Enter XXX when finished>>> :")
    if house_name.upper() == "XXX":
        break

def main():
print("Welcome!\n")

n_events = get_number_of_events()
events_names = get_events_names(n_events)
print()
data = get_data(events_names)
print()
for house_name, event_data in data:
    print ("House " + house_name)

    for event_name, score in event_data:
        print ("\tEvent: %s Score: %i" % (event_name, score))

print("The Overall Winner is,", sorted(data, key=lambda(x,y): sum(n[1] for n in y), reverse=True),sum(event[1] for event in event_data))

    print ("Please enter the events points in ascending order.")
    scores = []
    for event_name in events:
        score = get_score(house_name, event_name)
        scores.append([event_name, score])
    data.append([house_name, scores])
return data

if __name__ == '__main__':
main()

Answer 1

假设您的实际程序中的缩进是正确的，并且这是Python 3.x（因为您似乎使用print作为函数），问题将在您的lambda语句中。一个很小的例子来展示你的问题 -

>>> a = lambda (x,y) : x+y
  File "<stdin>", line 1
    a = lambda (x,y) : x+y
               ^
SyntaxError: invalid syntax

在Python 3.x中，tuples不能成为lambda参数语法的一部分，也就是说你不能直接将元素解包为多个参数（可以在Python 2.x中完成）。相反，您需要使用单个变量，然后使用下标访问元组的每个元素。示例 -

print("The Overall Winner is,", sorted(data, key=lambda x: sum(n[1] for n in x[1]), reverse=True),sum(event[1] for event in event_data))

另外，这对我来说似乎是不可读的，你应该把它分解成多行（也许在打印之前将中间结果保存在不同的变量中，这样会更具可读性）。

正如你在评论中所说的那样 -

例如，在这张图片中，我想要最高的字符串以及要打印的总点数，如picture.
所示

如果您想要具有最高值的元素，则获取第一个元素，并且由于数组的元素是再次列表，请使用下标来获取其名称。示例 -

print("The Overall Winner is,", sorted(data, key=lambda x: sum(n[1] for n in x[1]), reverse=True)[0][0],sum(event[1] for event in event_data))

根据评论的最新要求，做 -

sortedlist = sorted(data, key=lambda x: sum(n[1] for n in x[1]), reverse=True)
print("The Overall Winner is,", sortedlist[0][0], sum(n[1] for n in sortedlist[0][1]))

代码中的语法无效

1 个答案: