员工建模

Question

我的代码编译得很好，除非显示输入的信息，我收到错误，我不明白：

**线程“main”中的异常java.lang.NullPointerException

在员工处。（Employee.java:18）

at unit11.main（unit11.java:50）**

我的代码附在下面。

public class Employee {
public Name name;
public Date date;
public Address address;
public String[] data;

public Employee(String first, String last, 
        int inMont, int inDay, int inYear,
        String inStreet, String inCity, String inState, String inZip){

    if (errorCheck(inMont, inDay, inYear, inState, inZip) == 1)
        System.out.println("Error in data. Please try again.");
    else{
        name = new Name(first, last);
        date = new Date(inMont, inDay, inYear);
        address = new Address(inStreet, inCity, inState, inZip);

        data[0] = name.firstName + " " + name.lastName;
        data[1] = date.month + " " + date.day + ", " + date.year;
        data[2] = address.street + ", " + address.city +  ", " + address.state + ", " + address.zip;
    }


}

public int errorCheck(int inMonth, int inDay, int inYear,String inState, String inZip){
    if(inMonth < 1 || inMonth > 12 || inYear < 1000 || 
            inDay < 1 || inDay > 31 || 
            ((inMonth == 4 || inMonth == 6 || inMonth == 9 || inMonth == 11) && inDay > 30) 
            || (inMonth == 2 && inDay > 29) || inState.length() != 2)
            return 1;

    else return 0;
}

}

//和unit11代码中的第50行（是雇员[i]部分）

 if(errorCheck(month, day, year, state, zip) ==1)
        System.out.println("Invalid data input. Please try again.");
    else{
        employees[i] = new Employee(firstName, lastName, month, day, year,          street, city, state, zip);
        i++;
    }

Answer 1

您的构造函数期望inZip成为int：

public Employee(String first, String last, 
    int inMont, int inDay, int inYear,
    String inStreet, String inCity, String inState, int inZip)

但它是String：

String zip = input.nextLine();

邮政编码不是整数，它们是字符串。更改构造函数/类/ etc.期待一个字符串。