Question

我正在使用NetComm dll来处理多用户。我的问题是，当我发送文本它工作正常，但当我截图时，它不起作用。我的客户端代码是

ms = new MemoryStream();
            bmpScreenshot.Save(ms, ImageFormat.Png);
            byte[] buffer;
            buffer  =imageToByteArray(bmpScreenshot);
            client.SendData(buffer);

将图像转换为字节数组的函数是：

 public byte[] imageToByteArray(System.Drawing.Image imageIn)
        {
            MemoryStream ms = new MemoryStream();
            imageIn.Save(ms, System.Drawing.Imaging.ImageFormat.Gif);
            return ms.ToArray();
        }

在接收端，我这样处理：

    Stream stream = new MemoryStream(Data); // Data is byte array 
    pictureBox1.Image = Image.FromStream(stream);
    pictureBox1.Refresh();

收到后我会在图片框中显示图片。

使用NetComm dll我只能以bytearray格式发送和接收数据。

NetComm dll为我提供了使用其id从客户端到另一个客户端进行通信的工具。当服务器启动它等待客户端时，一旦客户端连接，它开始以某种方式给他们id，如abc1，abc2，abc3。当abc1想要与abc3通信时，它只需输入abc3作为id而不是IP，并发送消息，该消息应该传递给abc3。

正如您所看到的，有两个客户端连接到服务器，并且都获得了像jack1和jack2这样的id。现在，如果他们想要彼此沟通，他们只需键入相应的ID并发送消息。

Answer 1

我试图建立一个简单的客户端 - ＆gt;客户端消息发送，这将是一个位图。当我尝试使用不同的端口时，我遇到了问题，但端口被阻止了，这就是问题所在。检查一下。检查代码，看看是否有帮助：

namespace CommTest
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        NetComm.Host host = new NetComm.Host(10010);
        NetComm.Client client1 = new NetComm.Client();
        NetComm.Client client2 = new NetComm.Client();

        private void Form1_Load(object sender, EventArgs e)
        {
            host.StartConnection();
            client1.Connect("localhost", 10010, "Jack");
            client2.Connect("localhost", 10010, "Jack2");
            client2.DataReceived += client2_DataReceived;
            client1.SendData(imageToByteArray(Image.FromFile("Bitmap1.bmp")), "Jack2");
        }

        void client2_DataReceived(byte[] Data, string ID)
        {
            Stream stream = new MemoryStream(Data); // Data is byte array 
            pictureBox1.Image = Image.FromStream(stream);
            // pictureBox1.Refresh(); works without it
        }

        public byte[] imageToByteArray(Image imageIn)
        {
            MemoryStream ms = new MemoryStream();
            imageIn.Save(ms, ImageFormat.Gif);
            return ms.ToArray();
        }

        private void Form1_FormClosed(object sender, FormClosedEventArgs e)
        {
            host.CloseConnection();
        }
    }
}

Answer 2

完整的服务器/客户端实现可能是这样的。您不需要实现2个不同的客户端程序，但客户端和服务器应该是不同的。这是一个如何使用广播＆gt;

的示例

Program.cs的

static class Program
{
    /// <summary>
    /// The main entry point for the application.
    /// </summary>
    [STAThread]
    static void Main(string[] argv)
    {
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        // if You run the program like "CommTest.exe 10010", than it will be host.
        // if You run it like "CommTest.exe localhost 10010", than it will be client connecting to localhost.
        if (argv.Length == 1)
        {
            Application.Run(new Form2(new Host(int.Parse(argv[0]))));
        }
        else
        {
            Application.Run(new Form1(new Client(argv[0], int.Parse(argv[1]))));
        }
    }
}

Form1.cs的

public partial class Form1 : Form
{
    public Form1(NetComm.Client client)
    {
        _client = client;
        InitializeComponent();
    }

    // there is a button to broadcast picture on the client.
    private void Button1_Click(object sender, EventArgs e)
    {
        // update the image that should be broadcasted as You like.
        _client.SendData(imageToByteArray(Image.FromFile("Bitmap1.bmp")));
    }

    NetComm.Client _client;

    private void Form1_Load(object sender, EventArgs e)
    {
        button1.Click += Button1_Click;
        _client.DataReceived += client_DataReceived;
    }

    void client_DataReceived(byte[] Data, string ID)
    {
        Stream stream = new MemoryStream(Data); // Data is byte array 
        pictureBox1.Image = Image.FromStream(stream);
    }

    public byte[] imageToByteArray(Image imageIn)
    {
        MemoryStream ms = new MemoryStream();
        imageIn.Save(ms, ImageFormat.Gif);
        return ms.ToArray();
    }

    private void Form1_FormClosed(object sender, FormClosedEventArgs e)
    {
        _client.Disconnect();
    }
}

Client.cs

class Client: NetComm.Client
{
    public Client(string ip, int port):base()
    {
        // in this example, the ids are not considered. In a real world situation Clients should send a first message to the host,
        // and host should reply with a free id. That id should be in the place of Guid.NewGuid().ToString()
        Connect(ip, port, Guid.NewGuid().ToString());
    }
}

Form2.cs

public partial class Form2 : Form
{
    public Form2(NetComm.Host host)
    {
        _host = host;
        InitializeComponent();
    }

    NetComm.Host _host;

    private void Form2_Load(object sender, EventArgs e)
    {
        button1.Click += Button1_Click;
    }

    // there is a button to close the connection on the host form.
    private void Button1_Click(object sender, EventArgs e)
    {
        _host.CloseConnection();
    }

    private void Form2_FormClosed(object sender, FormClosedEventArgs e)
    {
        _host.CloseConnection();
    }
}

Host.cs

class Host: NetComm.Host
{
    public Host(int port):base(port)
    {
        StartConnection();
        DataReceived += Host_DataReceived;
    }

    void Host_DataReceived(string ID, byte[] Data)
    {
        Brodcast(Data);
    }
}

使用NetComm dll向主持人

2 个答案: