Question

我想知道如何获取看起来像这样的数据集：

表1：

RecordID    Code
A   351
A   352
A   353
A   354

看起来像这样：

表2：

您已经可以假设我使用我在下面创建的列标题创建了第二个表

RecordID    351 352 353 354 355 356
   A         Y   Y   Y   Y   N   N

提前感谢您的帮助。

Answer 1

SELECT RecordID,
    CASE WHEN SUM(CASE WHEN Code = 351 THEN 1 ELSE 0 END) = 1 THEN 'Y' ELSE 'N' AS [351],
    CASE WHEN SUM(CASE WHEN Code = 352 THEN 1 ELSE 0 END) = 1 THEN 'Y' ELSE 'N' AS [352],
    CASE WHEN SUM(CASE WHEN Code = 353 THEN 1 ELSE 0 END) = 1 THEN 'Y' ELSE 'N' AS [353],
    CASE WHEN SUM(CASE WHEN Code = 354 THEN 1 ELSE 0 END) = 1 THEN 'Y' ELSE 'N' AS [354],
    CASE WHEN SUM(CASE WHEN Code = 355 THEN 1 ELSE 0 END) = 1 THEN 'Y' ELSE 'N' AS [355],
    CASE WHEN SUM(CASE WHEN Code = 356 THEN 1 ELSE 0 END) = 1 THEN 'Y' ELSE 'N' AS [356]
FROM yourTable
GROUP BY RecordID

Answer 2

你可以尝试这样的事情：

select
    RecordID,
    iif(sum(iif([Code]=351,1,0))>0,'Y','N'),
    iif(sum(iif([Code]=352,1,0))>0,'Y','N'),
    iif(sum(iif([Code]=353,1,0))>0,'Y','N'),
    iif(sum(iif([Code]=354,1,0))>0,'Y','N'),
    iif(sum(iif([Code]=355,1,0))>0,'Y','N'),
    iif(sum(iif([Code]=356,1,0))>0,'Y','N')
from table
group by RecordID

使用多列将重复行合并为一行

2 个答案: