Question

比如说我有一张表，其中包含客户在咖啡馆时的活动说明。（我正在处理的实际表的隐喻）

Customer    Borrowed Book   Ordered Drink   Has Company
1               1       
1                                1  
1                                               Yes
2                                1  
3                                1  
3                                               Yes
4               1                1  
4                                1

我希望以这种方式组合行

Customer    Borrowed Book   Ordered Drink   Has Company
1               1                 1            Yes
2                                 1 
3                                 1            Yes
4               1                 2

我自己加入了coalesce，但它没有给出我想要的结果。

Answer 1

您可以通过分组，

执行此操作

select Customer,sum([borrowed book]), sum([ordered drink]), max([has company])
from customeractivity group by Customer

Answer 2

根据你的评论，初始表是临时表，尝试将结果作为cte结果，然后对其进行聚合，如下面的查询。

   ; WITH cte_1
      AS
     (  //your query to return the result set)
   SELECT customer,sum([borrowed book]) BorrowedBook, 
        sum([ordered drink]) OrderedDrink, 
        max([has company]) HasCompany
   FROM cte_1
   GROUP BY Customer

Answer 3

使用分组依据：

DECLARE @tblTest as Table(
    Customer INT,
    BorrowedBook INT,
    OrderedDrink INT,
    HasCompany BIt
)

INSERT INTO @tblTest VALUES
(1,1,NULL,NULL)
,(1,NULL,1,NULL)
,(1,NULL,NULL,1)
,(2,NULL,1,NULL)
,(3,NULL,1,NULL)
,(3,NULL,NULL,1)
,(4,1,1,NULL)
,(4,NULL,1,NULL)

SELECT 
    Customer,
    SUM(ISNULL(BorrowedBook,0)) AS BorrowedBook,
    SUM(ISNULL(OrderedDrink,0)) AS OrderedDrink,
    CASE MIN(CAST(HasCompany AS INT)) WHEN 1 THEN 'YES' ELSE '' END AS HasCompany
FROM @tblTest
GROUP BY Customer

Answer 4

不确定，为什么你会在群组中遇到错误。

你的合并应该是正确的。请参阅以下方式。

Select customer
, case when [borrowed] = 0 then NULL else [borrowed] end as [borrowed]
, case when [ordered] = 0 then NULL else [ordered] end as [ordered]
, case when [company] = 1 then 'Yes' end as company
from 
(
    Select customer,
    coalesce(
    case when (case when borrowed = '' then null else borrowed end) = 1 then 'borrowed' end,
    case when (case when ordered = '' then null else ordered end) = 1 then 'ordered' end,
    case when (case when company = '' then null else company end) = 'Yes' then 'company' end
    ) val
    from Table
) main
PIVOT
(
    COUNT (val)
    FOR val IN ( [borrowed], [ordered], [company] )
) piv

输出：

customer | borrowed | ordered | company
---------------------------------------
1           1           1           Yes
2           NULL        1           NULL
3           NULL        1           Yes

将多行合并为一行

4 个答案: