如何选择具有一个不同值和多个重复值的行？

Question

我有一张这样的表：

Timer timer = new Timer();
            TimerTask doAsynchronousTask = new TimerTask() {       
                @Override
                public void run() {
                    handler.post(new Runnable() {
                        public void run() {       
            ScrollView sv =(ScrollView)findViewById(R.id.scrl);
            sv.scrollTo(0, 10);
                        }
                    });
                }
            };
            timer.schedule(doAsynchronousTask, 0, 100000);

现在我要选择第一行和第四行。因为它们具有相同的// mytable +----+--------------------------+---------------+-----------------+ | id | Email | IP | cookies | +----+--------------------------+---------------+-----------------+ | 1 | jack.123@gmail.com | 172.95.65.7 | 5c6ffbdd40d95 | | 2 | ali.mngvv@yahoo.com | 84.15.2.4 | 26b73a21e63c3 | | 3 | redhat1931@gmail.com | 124.54.32.1 | e0e904b73a2fe | | 4 | peter_1998@gmail.com | 172.95.65.7 | 5c6ffbdd40d95 | | 5 | b.batman@ymail.com | 56.23.41.3 | b23a51a63edf4 | | 6 | ali.mngvv@yahoo.com | 84.15.2.4 | 26b73a21e63c3 | +----+--------------------------+---------------+-----------------+ ，相同的IP和不同的Cookies。我怎样才能选择它们？

我想要输出

Email

Answer 1

您可以将exists用作

select m1.* from mytable m1
where exists (
  select 1 from mytable m2
  where 
  m1.Email <> m2.Email
  and m1.IP = m2.IP
  and m1.cookies = m2.cookies
)

Answer 2

试试这个，它会帮助你

 SELECT id, Email,IP, cookies, COUNT(*) FROM mytable GROUP BY IP, cookies HAVING COUNT(*) > 1

Answer 3

这里的解决方案没有使用子查询，基本上是另一种查询方式。

SELECT m1.*
FROM mytable m1,mytable m2
WHERE (m1.`Email`<> m2.`Email`) AND (m1.`IP`=m2.`IP`) AND (m1.`cookies`=m2.`cookies`);