Question

创建一个函数get_algorithm_result来实现下面的算法

Get a list of numbers L1, L2, L3....LN as argument
Assume L1 is the largest, Largest = L1
Take next number Li from the list and do the following
If Largest is less than Li
Largest = Li
If Li is last number from the list then
return Largest and come out
Else repeat same process starting from step 3

这是我的代码：

def get_algorithm_result(listNumb):
 largest = listNumb[0]
 i = 1
 for i in range(i, len(listNumb)):
  if largest < listNumb[i]:
   largest = listNumb[i]
   i =i + 1
   continue
 return largest


>>> print( get_algorithm_result([4,7,1,9,12,2,1]) )
4

我错了什么？我希望它返回/打印在get_algorithm_result（）上调用的任何给定列表的最大数字。

Answer 1

该算法会跳过数字，因为它（1）在身体中使用for..in和（2）增量i。

Answer 2

这是一个经过多次黑客攻击的解决方案： def get_algorithm_result(listNumb): largest = listNumb[0] for i in range(1, len(listNumb)): if largest < listNumb[i]: largest = listNumb[i] continue return largest

Answer 3

您无需跟踪或为i分配值（您根本不需要i），您只需跟踪哪个值最大：

>>> def get_largest(listNumb):
...    largest = listNumb[0] # assume first value is the largest
...    for value in listNumb: # Take next number Li from the list
...       if largest < value: # If Largest is less than Li
...           largest = value # Largest = Li
...    return largest
...
>>> get_largest([1,1,1,32,42,5423,-1,4])
5423

Answer 4

我的解决方案使用while循环。我也试图照顾这些条件： - 如果李是列表中的最后一个号码那么 - 返回最大并出来

...VALUES ('', '$name', '$text', current_timestamp, '$catid', '1')...

Answer 5

def get_algorithm_result(numbers):
  largest = numbers[0]
  for i in numbers:
    if largest < i:
      largest = i
return largest

Answer 6

算法：

def get_algorithm_result(num_list):    
    largest =num_list[0]        
    for item in range(0,len(num_list)):    
        if largest < num_list[item]:                
            largest = num_list[item]    
    return largest

创建函数get_algorithm_result来实现算法

6 个答案: