Question

我有两个矩阵，我想以交替的方式交替交织/交错/堆叠在彼此/ rbind之上。

ranks=1:3
names=c("Karl", "Klaus", "Mary")
x <- cbind(ranks, names)

universities=c("Cape Town", "London", "Berlin")
y <- cbind(rep("", 3), universities)

在x的一行之后，我需要一行y：

     [,1] [,2]       
[1,] "1"  "Karl"     
[2,] ""   "Cape Town"
[3,] "2"  "Klaus"      
[4,] ""   "London"   
[5,] "3"  "Mary"   
[6,] ""   "Berlin"

我试过matrix(rbind(x, y), ncol=2)（如果我有两个字符串似乎可以解决问题）没有效果

Answer 1

以下是两种选择。

首先，假设我们必须从＆＃34; x＆＃34;开始和＆＃34; y＆＃34;，您可以尝试{＆＃34; gdata＆＃34;}中的interleave包：

library(gdata)
interleave(x, y)
#      ranks names      
# [1,] "1"   "Karl"     
# [2,] ""    "Cape Town"
# [3,] "2"   "Klaus"    
# [4,] ""    "London"   
# [5,] "3"   "Mary"     
# [6,] ""    "Berlin"

其次，假设我们可以从＆＃34; rank＆＃34;，＆＃34; names＆＃34;，＆＃34; university＆＃34;开始，你可以使用base R，如下所示：

cbind(c(t(cbind(ranks, ""))), c(t(cbind(names, universities))))
#      [,1] [,2]       
# [1,] "1"  "Karl"     
# [2,] ""   "Cape Town"
# [3,] "2"  "Klaus"    
# [4,] ""   "London"   
# [5,] "3"  "Mary"     
# [6,] ""   "Berlin"

然而，更好的选择是使用类似melt的内容（来自＆＃34; reshape2＆＃34;或＆＃34; data.table＆＃34;）。这将允许您添加另一个变量，该变量指示值表示的测量类型。

library(data.table)
melt(data.table(ranks, names, universities), "ranks")
#    ranks     variable     value
# 1:     1        names      Karl
# 2:     2        names     Klaus
# 3:     3        names      Mary
# 4:     1 universities Cape Town
# 5:     2 universities    London
# 6:     3 universities    Berlin

或者，为了符合您的预期顺序：

library(data.table)
setorder(melt(data.table(ranks, names, universities), "ranks"), ranks)[]
#    ranks     variable     value
# 1:     1        names      Karl
# 2:     1 universities Cape Town
# 3:     2        names     Klaus
# 4:     2 universities    London
# 5:     3        names      Mary
# 6:     3 universities    Berlin

交替，交织或交织两个矩阵

1 个答案: