这是代码,使用递归,我试图解决最短路径的迷宫,但它用更长的方式解决,我真的不明白为什么。这是递归代码:
public boolean findPath(int row, int col) {
board[row][col].visit();
if ((col == 7) && (row == 7)) {
board[row][col].selectCell();
return true;
}
if ((row > 0) && !board[row - 1][col].marked() &&
!board[row - 1][col].blocked() && !board[row - 1][col].visited()) {
block(row, col);
if (findPath(row - 1, col)) {
board[row][col].selectCell();
return true;
}
unblock(row, col);
}
if ((row < 7) && !board[row + 1][col].marked() &&
!board[row + 1][col].blocked() && !board[row + 1][col].visited()) {
block(row, col);
if (findPath(row + 1, col)) {
board[row][col].selectCell();
return true;
}
unblock(row, col);
}
if ((col > 0) && !board[row][col - 1].marked() &&
!board[row][col - 1].blocked() && !board[row][col - 1].visited()) {
block(row,col);
if (findPath(row, col - 1)) {
board[row][col].selectCell();
return true;
}
unblock(row,col);
}
if ((col < 7) && !board[row][col + 1].marked() &&
!board[row][col + 1].blocked() && !board[row][col + 1].visited()) {
block(row,col);
if (findPath(row, col + 1)) {
board[row][col].selectCell();
return true;
}
unblock(row,col);
}
return false;
}
它是8x8板,块功能如下:
public void block(int row, int col) {
if (row > 0) {
board[row - 1][col].block();
}
if (row < 7) {
board[row + 1][col].block();
}
if (col > 0) {
board[row][col - 1].block();
}
if (col < 7) {
board[row][col + 1].block();
}
}
任何帮助都会非常适合!
答案 0 :(得分:2)
试试这个,它应该可以工作并直接完成:
public boolean findPath(int row, int col) {
board[row][col].visit();
if ((col == 7) && (row == 7)) {
board[row][col].selectCell();
return true;
}
if ((row < 7) && !board[row + 1][col].marked() &&
!board[row + 1][col].blocked() && !board[row + 1][col].visited()) {
block(row, col);
if (findPath(row + 1, col)) {
board[row][col].selectCell();
return true;
}
unblock(row, col);
}
if ((col > 0) && !board[row][col - 1].marked() &&
!board[row][col - 1].blocked() && !board[row][col - 1].visited()) {
block(row,col);
if (findPath(row, col - 1)) {
board[row][col].selectCell();
return true;
}
unblock(row,col);
}
if ((col < 7) && !board[row][col + 1].marked() &&
!board[row][col + 1].blocked() && !board[row][col + 1].visited()) {
block(row,col);
if (findPath(row, col + 1)) {
board[row][col].selectCell();
return true;
}
unblock(row,col);
}
if ((row > 0) && !board[row - 1][col].marked() &&
!board[row - 1][col].blocked() && !board[row - 1][col].visited()) {
block(row, col);
if (findPath(row - 1, col)) {
board[row][col].selectCell();
return true;
}
unblock(row, col);
}
return false;
}
您需要更改订单。