DOM4J / XPATH解析文档

Question

Node existingUserNode = loginDoc.selectSingleNode("/returningUser");
String username = existingUserNode.selectSingleNode("/username").getText();
String password = existingUserNode.selectSingleNode("/password").getText();

代表

<?xml version="1.0" encoding="UTF-8"?><returningUser><username>user</username><password>password</password></returningUser>

返回null。

我不认为我的xpath是错的？或者我使用了错误的方法？

Answer 1

语法应该是./username和./password ...上面我通过引用root来看一个级别太高

Answer 2

试试这个

Node existingUserNode = loginDoc.selectSingleNode("/returningUser");
String username = existingUserNode.selectSingleNode("/username").getNodeValue();
String password = existingUserNode.selectSingleNode("/password").getNodeValue();