Question

我将数据导出到xml文件中。我正在循环浏览导出各种数据的数据库，并且需要检查xml文档以查看它是否已经存在，因为我正在导出数据。

当我尝试使用xPath查询xml文档时，它返回null。我是否必须保存xml文件然后重新加载它以使xPath工作？难道我做错了什么？这是我下面的测试代码。注意，我尝试使用xmlDoc.selectNodes以及xPath。仍然没有爱

这是控制台输出

<?xml version="1.0" encoding="UTF-8"?>

<root>
  <authors>
    <author>
      <name>Steven Rieger</name>
      <location>Illinois</location>
    </author>
    <author>
      <name>Dylan Rieger</name>
      <location>Illinois</location>
    </author>
  </authors>
</root>
org.dom4j.tree.DefaultDocument@e26948 [Document: name null]


public class TestXML
{

    public static void writeXmlDoc( Document document ) throws IOException
    {

        OutputFormat format = OutputFormat.createPrettyPrint();
        // lets write to a file
        XMLWriter writer = new XMLWriter( new FileWriter( "c:\\temp\\output.xml" ), format );
        writer.write( document );
        writer.close();

        // Pretty print the document to System.out
        writer = new XMLWriter( System.out, format );
        writer.write( document );
    }

    public static void main( String[] args ) throws Exception
    {
        org.dom4j.Document xmlDoc;
        List<Node> authors = null;
        Element author = null;
        try
        {
            xmlDoc = DocumentHelper.createDocument();
            Element root = xmlDoc.addElement( "root" );
            Element authorsElement = root.addElement( "authors" );
            Element author1 = authorsElement.addElement( "author" );
            author1.addElement( "name" ).addText( "Steven Rieger" );
            author1.addElement( "location" ).addText( "Illinois" );

            Element author2 = authorsElement.addElement( "author" );
            author2.addElement( "name" ).addText( "Dylan Rieger" );
            author2.addElement( "location" ).addText( "Illinois" );



            writeXmlDoc( xmlDoc );

//          authors = xmlDoc.selectNodes( "/authors" );

             XPath xpathSelector = DocumentHelper.createXPath("/authors");
             authors = xpathSelector.selectNodes( xmlDoc );

            for (Iterator<Node> authorIterator = authors.iterator(); authorIterator.hasNext();)
            {
                author = (Element) authorIterator.next();
                System.out.println( "Author: " + author.attributeValue( "name" ) );
                System.out.println( "  Location: " + author.attributeValue( "location" ) );
                System.out.println( "  FullName: " + author.getText() );
            }

            System.out.println( xmlDoc.toString() );
        } catch ( Exception e )
        {
            e.printStackTrace();
        }
    }
}

Answer 1

您的查询返回null，因为authors不是xml的根。您可以改用此xpath：

XPath xpathSelector = DocumentHelper.createXPath("/root/authors/author");

另一个问题是您首先将名称和状态存储为作者的子元素，但稍后您尝试将它们作为属性读取。见https://www.w3schools.com/xml/xml_dtd_el_vs_attr.asp 您可以尝试在循环中阅读它们：

System.out.println("Author: " + author.selectSingleNode("name").getText());
System.out.println("  Location: " + author.selectSingleNode("location").getText());

尝试在内存中创建的xml文档上使用xPath而不是文件

1 个答案: