我尝试使用 std :: copy C ++函数复制我创建的类中的对象列表,但该函数崩溃并显示下一条错误消息:
0x00007FFA91BAC570(msvcr120.dll)中的未处理异常 MyProject.exe:0xC0000005:访问冲突读取位置 0xFFFFFFFFFFFFFFFF。
该类非常简单,我不知道是什么原因导致复制功能因此类错误而崩溃。 该课程如下:
class XMLObjects
{
private:
int id;
string name;
int leftUpCornerX;
int leftUpCornerY;
int rightDownCornerX;
int rightDownCornerY;
bool isFound; //it's true if this object was found in the OR file and in the GT file
public:
XMLObjects(){}
XMLObjects(int _id){ id = _id; }
XMLObjects(int _id, string _name, int _leftUpCornerX, int _leftUpCornerY, int _rightDownCornerX, int _rightDownCornerY) { id = _id; name = _name; leftUpCornerX = _leftUpCornerX; leftUpCornerY = _leftUpCornerY; rightDownCornerX = _rightDownCornerX; rightDownCornerY = _rightDownCornerY; isFound = false; }
~XMLObjects(){}
void setID(int _id){ id = _id; }
void setName( string _name){ name=_name; }
void setLeftUpCorner(int _leftUpCornerX, int _leftUpCornerY){ leftUpCornerX = _leftUpCornerX; leftUpCornerY = _leftUpCornerY; }
void setRightDownCorner(int _rightDownCornerX, int _rightDownCornerY){ rightDownCornerX = _rightDownCornerX; rightDownCornerY = _rightDownCornerY; }
void objectWasFound(){ isFound = true; }
int getID(){ return id; }
string getName(){ return name; }
int getLeftUpCornerX(){ return leftUpCornerX; }
int getLeftUpCornerY(){ return leftUpCornerY; }
int getRightDownCornerX(){ return rightDownCornerX; }
int getRightDownCornerY(){ return rightDownCornerY; }
bool isObjectFound(){ return isFound; }
};
对复制功能的调用如下所示:
list<XMLObjects> objects;
objects.push_front(obj1);
objects.push_front(obj2);
objects.push_front(obj3);
list<XMLObjects> NewObjectsList;
std::copy(objects.begin(), objects.end(), NewObjectsList.begin());
有人可以帮忙吗?
答案 0 :(得分:4)
std::copy
不会调整输出大小,因此您必须先调整容器大小,或使用插入元素的特殊迭代器。
您可以使用以下代码。
std::copy(objects.begin(), objects.end(),
std::inserter(NewObjectsList, NewObjectsList.end()));
如评论中所述,在您的情况下,您可以直接复印一份:
list<XMLObjects> NewObjectsList = objects;