Question

我有像

这样的数据

|id|id_barang|in|out|stock|
|1|1|2|0|2|
|2|1|2|0|4|
|3|1|0|1|3|
|4|2|2|0|2|
|5|2|1|0|3|
|6|2|0|1|2|

我希望结果是id_barang

组

|Id_barang|sum(in)|sum(out)|first(stock)|
|1|4|1|2|
|2|3|1|2|

Answer 1

您可以将 MIN 功能用于第一个库存。它的工作方式与 SUM 或 COUNT 类似。

Answer 2

您可以尝试以下方式：

SELECT Id_barang, SUM(in), SUM(out), FIRST(stock)
FROM data
GROUP BY Id_barang

Answer 3

不幸的是Mysql不支持Window functions。试试这个

SELECT b.id_barang, 
       sum_in, 
       sum_out, 
       a.stock 
FROM   yourtable A 
       INNER JOIN (SELECT id_barang, 
                          Sum(in)  sum_in, 
                          Sum(OUT) sum_out, 
                          Min(id)  AS min_id 
                   FROM   yourtable 
                   GROUP  BY id_barang) B 
               ON a.id_barang = b.id_barang 
                  AND a.id = b.min_id

Answer 4

此查询通过Id_barang获取表组的所有记录。它给出了第一份库存记录 SELECT t1.Id_barang, sum(t1.in), sum(t1.out), (select min(t2.stock) from table_name t2 where t2.Id_barang = t1.Id_barang) FROM table_name t1 GROUP BY Id_barang

Answer 5

你可以这样查询：

SELECT id_barang,SUM(in) as total_in,SUM(out) as total_out,stock
FROM stock
GROUP BY id_barang

如果您发现任何错误，那么您必须更改您的列名称，我认为＆＃39;在＆＃39;和＆＃39; out＆＃39;无效。你改变了＆＃39; in＆＃39;进入＆＃39; in_change＆＃39;和＆＃39; out＆＃39;进入＆＃39; out_change＆＃39;。尝试使用此列，它可以根据需要使用。我确实试过......

SELECT id_barang,SUM(in_change) as total_in,SUM(out_change) as total_out,stock
FROM stock
GROUP BY id_barang

如何选择相同id和sum列的第一个数据相同的id sql

5 个答案: