为数据中的不同列选择数据和列的总和

Question

我有一张这样的表格（总结客户，每个人都有一些付款）：

customerID      Payments   InvoicCode
1                 1000         112
1                 250          456
2                 100          342
1                 20           232
2                 500          654
3                 300          230

我想要的是下面（每行客户付款的总和）：

customerID      Payments   InvoicCode   SumPayment
1                 1000         112        1270
1                 250          456        1270
2                 100          342        600
1                 20           232        1270
2                 500          654        600
3                 300          230        300

Answer 1

在多行中复制更宽范围的数据是不正常的正常形式。考虑更新付款或添加新客户付款的影响 - 您必须更新该客户的所有相关总计。

创建一个视图/存储过程会更简单，它可以在运行时为您提供总计，您可以在需要时调用它们：

create view CustomerTotals as

  select customerID
        ,sum(Payments) as SumPayment
    from mytable
group by customerID

然后你可以用select * from CustomerTotals引用它，输出如下：

customerID      SumPayment
1               1270
2               600
3               300

Answer 2

这是：

SELECT t.customerID,
       t.Payments,
       t.InvoicCode,
       aux.SumPayment
FROM tablename t
INNER JOIN
(SELECT customerID,
        SUM(Payments) as SumPayment
 FROM tablename
 GROUP BY customerID) aux ON t.customerID = aux.customerID

Answer 3

试试这个，（主要适用于任何rdbms ）

SELECT  a.*, b. totalPayment
FROM    paymentsTable a
            INNER JOIN
            (
                SELECT customerID, SUM(Payments) totalPayment
                FROM paymentsTable
                GROUP BY customerID
            ) b ON a.customerID = b.customerID

SQLFiddle Demo

Answer 4

select t1.*,sumPay
from table t1,
(select customerID,sum(Payments) as sumPay
 from table
 group by customerID) t2
where t1.cutomerID=t2.customerID

Answer 5

您可以创建视图或尝试这样的选择：

SELECT customerID, 
Payments, 
InvoicCode, 
(SELECT SUM(Payments) 
    FROM Customer IC 
    WHERE IC.customerID = OC.customerID )
FROM Customer  OC

Answer 6

将表格加入其自身的总和版本：

select mytable.customerID, Payments, InvoicCode, SumPayment
from mytable
join (select customerID, sum(Payments) as SumPayment from mytable group by 1) x
  on x.customerID = mytable.customerID

Answer 7

您可以使用子查询获取总和，然后将其与表格连接以添加其他列。

SELECT x2.customerID
  , x2.payments
  , x2.invoice
  , x1.sumpayment
FROM
(
  select customerID
   ,sum(Payments) as SumPayment
  from yourtable
  group by customerID
) x1
inner join yourtable x2
  ON x1.customerID = x2.customerid

请参阅SQL Fiddle with Demo

Answer 8

对于MSSQL

SELECT Т1.*, Т2.SumPayment
FROM TableName T1 INNER JOIN 
 ( SELECT customerId, SUM(Payments) SumPayment 
    FROM TableName
    GROUP BY customerID  
) T2 ON T1.customerID = T2.customerId

Answer 9

假设您的dbms是MS Sql-Server，您可以使用带有OVER子句的SUM(Payments)：

SELECT customerID, Payments,InvoicCode
   ,SumPayment=SUM(Payments)OVER(PARTITION BY customerID)
FROM t

SQL-Fiddle：http://sqlfiddle.com/#!3/2ac38/2/0

Answer 10

的 SqlFiddle ：

SELECT
       t.customerID     as customerID,
       t.Payments       as Payments,
       t.InvoicCode     as InvoicCode,
       total            as SumPayment
FROM
       theTable t, 
       (
          SELECT   customerId,
                   sum(Payments) as total
          FROM     theTable
          GROUP BY customerId
       ) tmp
WHERE  
       tmp.customerId = t.customerId