"id","gender","age","category1","category2","category3","category4","category5","category6","category7","category8","category9","category10"
1,"Male",22,"movies","music","travel","cloths","grocery",,,,,
2,"Male",28,"travel","books","movies",,,,,,,
3,"Female",27,"rent","fuel","grocery","cloths",,,,,,
4,"Female",22,"rent","grocery","travel","movies","cloths",,,,,
5,"Female",22,"rent","online-shopping","utiliy",,,,,,,
我需要重新格式化如下。
id gender age category rank
1 Male 22 movies 1
1 Male 22 music 2
1 Male 22 travel 3
1 Male 22 cloths 4
1 Male 22 grocery 5
1 Male 22 books NA
1 Male 22 rent NA
1 Male 22 fuel NA
1 Male 22 utility NA
1 Male 22 online-shopping NA
到目前为止,我的努力如下:
mini <- read.csv("coding/mini.csv", header=FALSE)
mini_clean <- mini[-1,]
df_mini <- melt(df_clean, id.vars=c("V1","V2","V3"))
sqldf('select * from df_mini order by "V1"')
现在我想知道为每个用户填写所有缺失类别的最佳方法是什么。 在这方面的任何帮助表示赞赏。
答案 0 :(得分:1)
考虑使用基函数reshape,因为这是从长到长的数据集整形/旋转的常规示例:
reshapedf <- reshape(df, varying = c(4:13),
v.names = c("category"),
timevar=c("rank"),
times = c(1:10),
idvar = c("id", "gender", "age"),
new.row.names = 1:1000,
direction = "long")
# ORDER RESULTING DATA FRAME
reshapedf <- reshapedf[with(reshapedf , order(id, gender, age)), ]
# RESET ROW NAMES
row.names(reshapedf) <- 1:nrow(reshapedf)
<强>输出强>
id gender age rank category
1 1 Male 22 1 movies
2 1 Male 22 2 music
3 1 Male 22 3 travel
4 1 Male 22 4 cloths
5 1 Male 22 5 grocery
6 1 Male 22 6 NA
7 1 Male 22 7 NA
8 1 Male 22 8 NA
9 1 Male 22 9 NA
10 1 Male 22 10 NA
...