我尝试从3个来源收集数据但这些是异步的。因此我试图计算回调。这是我为此目的编写的代码。
var http = require('http');
var data_str1 = '';
var data_str2 = '';
var data_str3 = '';
var ended = 0;
function callback1(response){
response.on('end', function(){ended++;});
response.on('data', function(data){
data_str1 += data;
});
}
function callback2(response){
response.on('end', function(){ended++;});
response.on('data', function(data){
data_str2 += data;
});
}
function callback3(response){
response.on('end', function(){ended++;});
response.on('data', function(data){
data_str3 += data;
});
}
http.get(process.argv[2], function(response){
callback1(response);
if (ended == 3) console.log(data_str1);
});
http.get(process.argv[3], function(response){
callback2(response);
if (ended == 3) console.log(data_str2);
});
http.get(process.argv[4], function(response){
callback3(response);
if (ended == 3) console.log(data_str3);
});
你能告诉我这段代码有什么问题吗?
答案 0 :(得分:6)
这是我的解决方案。我已经过测试并且有效。
var http = require('http');
var concat = require('concat-stream');
var urls = [];
var responses = [];
var count = 0;
for (var i = 2; i < process.argv.length; i++) {
urls.push(process.argv[i]);
}
function readResponse(index) {
http.get(urls[index], function(response) {
response.pipe(concat(function(data) {
responses[index] = data.toString();
count++;
if (count == 3) {
responses.forEach(function(response) {console.log(response);});
}
}));
});
}
for (var i = 0; i < urls.length; i++) {
readResponse(i);
}
答案 1 :(得分:1)
const http = require('http');
const bl = require('bl');
const results = [];
let count = 0;
function printResults () {
for (let i = 0; i < 3; i++) {
console.log(results[i])
}
}
function httpGet (index) {
http.get(process.argv[2 + index], function (response) {
response.pipe(bl(function (err, data) {
if (err) {
return console.error(err)
}
results[index] = data.toString()
count++
if (count === 3) {
printResults()
}
}))
})
}
for (let i = 0; i < 3; i++) {
httpGet(i)
}
答案 2 :(得分:0)
这里的问题是
if (ended == 3) console.log(data_str2);
将在callback2(response);
之后运行
它不等待response.on('end', function(){ended++;});
答案 3 :(得分:0)
我的解决方案,简单明了
const http = require('http')
const bl = require('bl')
const results = []
let count = 0
function printResults () {
for (let i = 0; i < 3; i++) {
console.log(results[i])
}
}
function httpGet (index) {
http.get(process.argv[2 + index], function (response) {
response.pipe(bl(function (err, data) {
if (err) {
return console.error(err)
}
results[index] = data.toString()
count++
if (count === 3) {
printResults()
}
}))
})
}
for (let i = 0; i < 3; i++) {
httpGet(i)
}
答案 4 :(得分:0)
在您的代码中,检查回调函数中的结束值(ended === 3)。我使用类似的方法解决了这个问题。请注意,我对所有三个网址都使用了一个回调函数
const http = require("http");
let url1 = process.argv[2];
let url2 = process.argv[3];
let url3 = process.argv[4];
let str1 = "";
let str2 = "";
let str3 = "";
let end = 0;
function cb(response, str) {
response.on("data", data => {
if (str === "str1") str1 += data;
if (str === "str2") str2 += data;
if (str === "str3") str3 += data;
});
response.on("end", () => {
end++;
if (end === 3) {
console.log(`${str1}\n${str2}\n${str3}`);
}
});
}
http.get(url1, response => {
cb(response, "str1");
});
http.get(url2, response => {
cb(response, "str2");
});
http.get(url3, response => {
cb(response, "str3");
});
答案 5 :(得分:-2)
我知道这是一个古老的问题,但是我只是想用另一种方法来分享我的丑陋解决方案。
const http = require('http');
let data1 = '';
let data2 = '';
let data3 = '';
http.get(process.argv[2], (res) => {
res.on('data', (data) => {
data1 += data;
})
res.on('end', () => {
http.get(process.argv[3], (res) => {
res.on('data', (data) => {
data2 += data;
})
res.on('end', () => {
http.get(process.argv[4], (res) => {
res.on('data', (data) => {
data3 += data;
})
res.on('end', () => {
console.log(data1); console.log(data2); console.log(data3);
})
})
})
})
})
})