Question

我正在制作毕达哥拉斯定理程序以解决缺失的一方，如果用户输入0作为值，则意味着这是缺少的一方需要解决。我的程序没有得到正确的答案。非常感谢您的帮助。

import java.util.Scanner;
import java.lang.Math;

public class pythagTheorem {
  static double a;
  static double b;
  static double c;
  static double newa;
  static double newb;
  static double newc;   

  public static void main(String[] args) {
     Scanner scan= new Scanner(System.in);
     System.out.println("Enter the value of a");
     a=scan.nextDouble();
     scan.nextLine();
     System.out.println("Enter the value of b");
     b=scan.nextDouble();
     scan.nextLine();
     System.out.println("Enter the value of c");
     c=scan.nextDouble();
     scan.nextLine();
     if(a==0)
     {
         newb=Math.pow(b, b);
         newc=Math.pow(c, c);
         double result=newc-newb;
         newa=Math.sqrt(result);        
     }      
     System.out.println("The value of a is " + newa);
  }
}

Answer 1

好！所以我用这个Java代码看到的问题是它不一定遵循实际的毕达哥拉斯定理。我看到如果（A == 0）然后执行实际的等式，但你必须记住变量A不是三角形的斜边！

A ^ 2 + B ^ 2 = C ^ 2（C是斜边）如果你想要它找到三角形的任何部分你必须记住导出方程式，这样你就可以找到缺失的一面！例如，你有A面和C面，但你想找到B面，那么该等式就是B ^ 2 = C ^ 2-A ^ 2。

最后，我看到你有newb = Math.pow（b，b）;这将为你自己的变量提供动力！即使是权力只有2，所以它将是newb = Math.pow（b，2）;

TIP！请记住将变量名称中的第二个单词（如numa）大写为numA

/* REMEMBER THAT A NUMBER MUST NEVER BE GREAT THAN C UNLESS IT IS THE UNKNOWN OR YOU WILL ENCOUNTER A NONREAL NUMBER BECAUSE YOU CAN'T SQUARE ROOT A NEGATIVE NUMBER*/
    import java.util.Scanner;
    import java.lang.Math;

    public class pythagTheorem {

        static double a;
        static double b;
        static double c;
        static double newa;
        static double newb;
        static double newc;

        public static void main(String[] args) {

            Scanner scan = new Scanner(System.in);
            System.out.println("Enter a ZERO for the unknown side!");

            System.out.println("Enter the value of side A :: ");
            a = scan.nextDouble(); 

            System.out.println("Enter the value of B :: ");
            b = scan.nextDouble();

            System.out.println("Enter the value of C :: ");
            c = scan.nextDouble();

            if (a == 0) {

                newc = Math.pow(c, 2);
                newb = Math.pow(b, 2);

                newa = Math.sqrt(newc - newb);

                System.out.println("Your missing side is :: " + newa);

            }
            else if(b == 0){

                newc = Math.pow(c, 2);
                newa = Math.pow(a, 2);

                newb = Math.sqrt(newc - newa);

                System.out.println("Your missing side is :: " + newb);
            }
            else if(c == 0){

                newa = Math.pow(a, 2);
                newb = Math.pow(b, 2);

                newc = Math.sqrt(newa + newb);

                System.out.println("Your missing side is :: " + newc);
            }
            else
                System.out.println("Sorry! There is an error!");


        }
    }

毕达哥拉斯定理计划的错误

1 个答案: