Question

我对c ++很新，我想知道以下是否可行：

考虑你有

class Client {
public:
    Client(string firstname, string lastname);
// ...
}

您是否可以重载>>运算符以使用您刚刚输入的输入生成新对象？

喜欢

istream& operator>> (istream& is, Client* client) {
    cout << "First Name: ";
    is >> client->firstName;
    cout << "Last Name: ";
    is >> client->lastName;
    return is;
}

使用重载的＆gt;＆gt;基于用户输入创建对象的正确方法是什么？操作员，你会怎么做？如果我想这样做，我将不得不写

Client* client;
cin >> client;

但是那时，客户端已经创建了......

感谢

Answer 1

你可以这样做（客户端指针需要通过引用传递，然后读取临时变量并创建客户端）：

istream& operator >> (istream& is, Client * &client) {
    string firstname, lastname;
    cout << "First Name: ";
    is >> firstname;
    cout << "Last Name: ";
    is >> lastname;
    client = new Client(firstname, lastname);
    return is;
}

Client* client;
cin >> client;
// use client
delete client;

但我不建议一般。更清洁的方法是

istream& operator >> (istream& is, Client &client) {
    cout << "First Name: ";
    is >> client.firstname;
    cout << "Last Name: ";
    is >> client.lastname;
    return is;
}

Client client;
cin >> client;
// use client
// client destroyed on scope exit

使用重载＆gt;＆gt;调用CPP构造函数操作者

1 个答案: