Question

问题：根据文档编号搜索员工。输入：文件清单。和文档类型预期结果：相应文档号 AND 类型的员工列表。

我有的表：

表1：员工 empID - person

表2：文件 docNo - docType - id

请注意：employee.person.id = doc.parent.id - 数据库设计也是如此写了这样的查询：

SELECT employee 
from Employee employee, Document doc 
WHERE doc.docType IN :docTypeList 
and doc.docNo IN :docNoList 
and employee.person.id = doc.parent.id

我知道它不会起作用，因为＆＃34; doc.docType IN：docTypeList和doc.docNo IN：docNoList＆＃34;，但无法想到替代方案。任何导致修改查询，以便我可以处理docTypeList和docNoList来查找匹配它们的员工。

Answer 1

看起来您只需要在ID值上加入表格，并在select子句中添加正确的值：

SELECT a.employee, b.docType, b.docNo
FROM employee a JOIN document b
ON a.empID=b.id

这是一个使用原始问题中的命名约定（类型）的示例：

SELECT emp.employee, doc.docType, doc.docNo
FROM Employee emp JOIN document doc
ON emp.empID=doc.id

与您的问题无关，但在使用tablename别名时，您应该缩短别名，否则您每次都可以输入表的名称。别名的要点是通过使用缩短的表名使代码更清晰，更容易键入。见上文 - 我将员工别名更改为＆＃34; emp＆＃34;

Answer 2

我有更多的SQL服务器，所以假设你的列表参数就像tableTypes ....

SELECT employee 
from Employee employee
INNER JOIN Document doc ON doc.parent.id = employee.person.id
WHERE 
doc.docType IN ( Select doctype FROM :docTypeList )
and doc.docNo IN (Select doc no FROM :docNoList )

Answer 3

当您需要将参数列表传递给IN（）时，解决方案是分解列表并将每个项目作为单独的参数传递给SQL语句。

假设MySQL + PDO：

$paramCount = 0;
$params = [];  // holds parameter values
$typesParamNames = $numbersParamNames = []; // parameter names for each list

// document types
foreach ($docTypeList as $val)
{
    ++$paramCount;
    $paramName = ":p{$paramCount}";
    $params[$paramName] = $val;
    $typesParamNames[] = $paramName;
}

// document numbers
foreach ($docNoList as $val)
{
    ++$paramCount;
    $paramName = ":p{$paramCount}";
    $params[$paramName] = $val;
    $numbersParamNames[] = $paramName;
}

// build the SQL
$typesSqlFragment = implode(',', $typesParamNames);
$numbersSqlFragment = implode(',', $numbersParamNames);
$sql = "SELECT employee from Employee employee, Document doc WHERE doc.docType IN ($typesSqlFragment) and doc.docNo IN ($numbersSqlFragment) and employee.person.id = doc.parent.id";
$stmt = $dbh->prepare($sql);

// pass the collected parameters values to the prepared statement
foreach ($params as $name => $val) {
    $stmt->bindParam($name, $val);
}

// run it
$stmt->execute();

查询基于两个不同列表检索项目列表

3 个答案: