由于某种原因,行“new1 = [chr(x)for x in new]”不能采用浮点数。我将“新”列表中的所有ASCII整数转换回带有字符的列表,根据它们各自的ASCII号,该列表将保存为new1。
if de == "d":
num = input("input ur number: ")
key = int(input("Decryption key?"))
num = [int(x) for x in num.split()]
new = [x /key for x in num]
new1 = [chr(x) for x in new]
这是错误:
- Traceback(最近一次调用最后一次): 文件“C:\ Python34 \ Encryptiontrue.py”,第23行,in new1 = [chr(x)for x in new]
- 文件“C:\ Python34 \ Encryptiontrue.py”,第23行,in new1 = [chr(x)for x in new]
- TypeError:期望的整数参数,浮点数
完整代码:
de = input("Decrypt or encrypt?: ")
if de == "e":
word = input("input ur text: ")
word = word.lower()
new = list(word)
key = int(input("what number by?: "))
new1 = [ord(x) * user for x in new]
new2 = " ".join(str(x) for x in new1)
print(new2)
if de == "d":
num = input("input ur number: ")
key = int(input("Decryption key?"))
num = [int(x) for x in num.split()]
new = [x /key for x in num]
new1 = [chr(x) for x in new]
答案 0 :(得分:1)
更改
JTextField findtext = new JTextField();
//findtext.setBounds(112,549, 63, 24);
frame.add(findtext,BorderLayout.BEFORE_FIRST_LINE);
findtext.addKeyListener(new KeyAdapter() {
public void keyPressed(KeyEvent evt) {
int code = evt.getKeyCode();
if(code == KeyEvent.VK_ENTER){
String find = findtext.getText().toLowerCase();
tarea.requestFocusInWindow();
//findtext.requestFocus();
//findtext.requestFocusInWindow();
if (find != null && find.length()> 0) {
Document document = tarea.getDocument();
int findLength = find.length();
try {
//int pos=0;
boolean found = false;
if (pos + findLength > document.getLength()) {
pos = 0;
}
while (pos + findLength <= document.getLength()) {
String match = document.getText(pos, findLength).toLowerCase();
if (match.equals(find)) {
found = true;
break;
}
pos++;
}
if (found) {
Rectangle viewRect = tarea.modelToView(pos);
tarea.scrollRectToVisible(viewRect);
tarea.setCaretPosition(pos + findLength);
tarea.moveCaretPosition(pos);
pos += findLength;
//Thread.sleep(2000);
// findtext.requestFocusInWindow();
}
} catch (Exception exp) {
exp.printStackTrace();
}
}
}//findtext.requestFocusInWindow();
}
});
/*control back to textarea*/
tarea.addKeyListener(new KeyAdapter() {
public void keyPressed(KeyEvent evt) {
int code = evt.getKeyCode();
if(code == KeyEvent.VK_ENTER){
String find = findtext.getText().toLowerCase();
tarea.requestFocusInWindow();
//findtext.requestFocus();
//findtext.requestFocusInWindow();
if (find != null && find.length()> 0) {
Document document = tarea.getDocument();
int findLength = find.length();
try {
//int pos=0;
boolean found = false;
if (pos + findLength > document.getLength()) {
pos = 0;
}
while (pos + findLength <= document.getLength()) {
String match = document.getText(pos, findLength).toLowerCase();
if (match.equals(find)) {
found = true;
break;
}
pos++;
}
if (found) {
Rectangle viewRect = tarea.modelToView(pos);
tarea.scrollRectToVisible(viewRect);
tarea.setCaretPosition(pos + findLength);
tarea.moveCaretPosition(pos);
pos += findLength;
//Thread.sleep(2000);
// findtext.requestFocusInWindow();
}
} catch (Exception exp) {
exp.printStackTrace();
}
}
}//findtext.requestFocusInWindow();
}
});
/*search filed ends*/
到
new = [x / key for x in num]
在Python 3中,new = [x // key for x in num]
表示“真正的除法”,它总是返回一个浮点数。 /
表示“地板划分”。如果两个参数都是整数,则Floor division将返回一个整数。有关详细信息,请参阅{{3}}。