我试图通过我的iOS应用程序向我的localhost服务器发帖。
正确执行此curl命令（从我的iOS应用程序生成的字符串中复制了JSON）：
curl -XPOST -H "Content-Type: application/json" -d '{"appuser":{"id":0,"birthday_month":2,"hispanic_origin":"0","marital_status":"1","age":25,"idfa":"A84F55A7-3C6F-4A2E-9379-AB9895863C25","profiled":1,"dob":"2\/16\/1989","quality":1,"zip":"53593","device_type":"x86_64","income":"7","race":"0","children":"36","birthday_year":1989,"education":"7","employment_status":"0","gender":0,"birthday_day":16}}' http://localhost:3000/api/v1/appusers?access_token=6434ba7036431f2c8d12572eab0f2746
在我的iOS应用中，我创建了这样的POST：
NSString *urlStr = [@"http://localhost:3000/api/v1/appusers?access_token=" stringByAppendingString:[NSString stringWithFormat:@"6434ba7036431f2c8d12572eab0f2746"]];
NSURL *url = [NSURL URLWithString:urlStr];
NSURLSession *session = [NSURLSession sharedSession];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
request.HTTPBody = [newNewString dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPMethod = @"POST";
NSURLSessionDataTask *postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
}];
[postDataTask resume];
但我不断从我的服务器得到400回复说明：
ActionController::ParameterMissing (param is missing or the value is empty: appuser):
app/controllers/api/v1/appusers_controller.rb:36:in `appuser_params'
app/controllers/api/v1/appusers_controller.rb:10:in `create'
问题似乎是在发送到我的rails应用程序之前如何转义JSON。在我的服务器中它看起来像这样：
Parameters: {"{\"appuser\":`{\"id\":0,\"birthday_month\":2,\"hispanic_origin\":\"0\",\"marital_status\":\"1\",\"age\":25,\"idfa\":\"A84F55A7-3C6F-4A2E-9379-AB9895863C25\",\"profiled\":1,\"dob\":\"2\\/16\\/1989\",\"quality\":1,\"zip\":\"53593\",\"device_type\":\"x86_64\",\"income\":\"7\",\"race\":\"0\",\"children\":\"36\",\"birthday_year\":1989,\"education\":\"7\",\"employment_status\":\"0\",\"gender\":0,\"birthday_day\":16}}"=>nil, "access_token"=>"6434ba7036431f2c8d12572eab0f2746"}`
但是当我在我的应用程序中注销时，我看到了：
{"appuser":{
"id" : 0,
"birthday_month" : 2,
"hispanic_origin" : "0",
"marital_status" : "1",
"age" : 25,
"idfa" : "A84F55A7-3C6F-4A2E-9379-AB9895863C25",
"profiled" : 1,
"dob" : "2\/16\/1989",
"quality" : 1,
"zip" : "53593",
"device_type" : "x86_64",
"income" : "7",
"race" : "0",
"children" : "36",
"birthday_year" : 1989,
"education" : "7",
"employment_status" : "0",
"gender" : 0,
"birthday_day" : 16
}}
我还尝试剥离换行符和空格以在我的iOS应用中获取此内容：
{"appuser":{"id":0,"birthday_month":2,"hispanic_origin":"0","marital_status":"1","age":25,"idfa":"A84F55A7-3C6F-4A2E-9379-AB9895863C25","profiled":1,"dob":"2\/16\/1989","quality":1,"zip":"53593","device_type":"x86_64","income":"7","race":"0","children":"36","birthday_year":1989,"education":"7","employment_status":"0","gender":0,"birthday_day":16}}
我的直觉说问题就在于我编码字符串的地方：
request.HTTPBody = [newNewString dataUsingEncoding:NSUTF8StringEncoding];
以下是我创建JSON的方式：
NSMutableDictionary *appuserDictionary = [NSMutableDictionary dictionary];
NSEntityDescription *entity = [self.appuser entity];
NSDictionary *attributes = [entity attributesByName];
for (NSString *attribute in attributes) {
id attributeValue = [self.appuser valueForKey: attribute];
if (attributeValue) {
[appuserDictionary setObject:attributeValue forKey:attribute];
}
}
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:appuserDictionary
options:NSJSONWritingPrettyPrinted // Pass 0 if you don't care about the readability of the generated string
error:&error];
if (! jsonData) {
NSLog(@"Got an error: %@", error);
} else {
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSString *appuserJsonString = [NSString stringWithFormat:@"{%@:%@}", @"\"appuser\"", jsonString];
NSString *newString = [[appuserJsonString componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]] componentsJoinedByString:@""];
NSString *newNewString = [[newString componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@" "]] componentsJoinedByString:@""];
NSLog(appuserJsonString);
NSLog(newNewString);
我是iOS的新手，所以我希望我能错过一些愚蠢的东西。
我的Rails控制器（ApiController基本上只验证access_token）：
module Api
module V1
class AppusersController < ApiController
def show
@appuser = Appuser.find(params[:id])
end
def create
@appuser = Appuser.new(appuser_params)
respond_to do |format|
if @appuser.save
@appuser.update_location
format.json { render action: 'show', status: :created, location: @appuser }
else
format.json { render json: @appuser.errors, status: :unprocessable_entity }
end
end
end
def update
@appuser = Appuser.find(params[:id])
respond_to do |format|
if @appuser.update(appuser_params)
format.json { head :no_content }
else
format.json { render json: @appuser.errors, status: :unprocessable_entity }
end
end
end
private
# Never trust parameters from the scary internet, only allow the white list through.
def appuser_params
params.require(:appuser).permit(:age, :income, :city, :zip, :county, :state, :state_code, :country, :gender, :employment_status, :education, :marital_status, :email, :username, :remember_token, :created_at, :updated_at, :coins, :pending_coins, :userGo, :birthday_month, :birthday_day, :birthday_year, :profiled, :quality, :race, :children, :hispanic_origin)
end
end
end
end
答案 0 :(得分：1)
You have to tell the server that your body is in a JSON format by adding the right request header:
...
request.HTTPBody = [newNewString dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPMethod = @"POST";
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
...