Question

我有以下字符串，我试图解析为JSON对象，然后变成一个javascript数组：

"[{\"items\":\"nut\",\"sales\":6,\"prices\":10},\n {\"items\":\"bolt\",\"sales\":8,\"prices\":20},\n {\"items\":\"cam\",\"sales\":0,\"prices\":15},\n {\"items\":\"cog\",\"sales\":3,\"prices\":20}]"

我删除了换行符来获取

"{\"items\":\"nut\",\"sales\":6,\"prices\":10}, {\"items\":\"bolt\",\"sales\":8,\"prices\":20}, {\"items\":\"cam\",\"sales\":0,\"prices\":15}, {\"items\":\"cog\",\"sales\":3,\"prices\":20}"

我试过这个

   dd = "[{\"items\":\"nut\",\"sales\":6,\"prices\":10},\n {\"items\":\"bolt\",\"sales\":8,\"prices\":20},\n {\"items\":\"cam\",\"sales\":0,\"prices\":15},\n {\"items\":\"cog\",\"sales\":3,\"prices\":20}]";
   dd = dd.replace(/\\n/g, '');
   dd = dd.replace(/[\[\]']+/g,'');
   console.log(JSON.parse(dd));
   dd= JSON.parse(dd));

但是由于dd.items为null

，这实际上并没有因为某种原因解析json

Answer 1

但是由于dd.items的原因，这实际上并没有解析json 空

无需从字符串中删除换行符\n，只需直接执行JSON.parse

＆＃13;

var dd = JSON.parse( "[{\"items\":\"nut\",\"sales\":6,\"prices\":10},\n {\"items\":\"bolt\",\"sales\":8,\"prices\":20},\n {\"items\":\"cam\",\"sales\":0,\"prices\":15},\n {\"items\":\"cog\",\"sales\":3,\"prices\":20}]" );
console.log(dd);

＆＃13;

此外，dd是一个数组，因此您需要迭代dd才能获得items

dd.forEach( s => console.log(s.items) );

Answer 2

let x = "[{\"items\":\"nut\",\"sales\":6,\"prices\":10},\n {\"items\":\"bolt\",\"sales\":8,\"prices\":20},\n {\"items\":\"cam\",\"sales\":0,\"prices\":15},\n {\"items\":\"cog\",\"sales\":3,\"prices\":20}]";
let y = x.substr(1, x.length - 2).split(',\n').map(JSON.parse);
console.log(y);

Answer 3

使用 JSON.parse(dd); 功能删除此

Answer 4

＆＃13;

var data="[{\"items\":\"nut\",\"sales\":6,\"prices\":10},\n {\"items\":\"bolt\",\"sales\":8,\"prices\":20},\n {\"items\":\"cam\",\"sales\":0,\"prices\":15},\n {\"items\":\"cog\",\"sales\":3,\"prices\":20}]";

//use JSON parse that will convert the string to JSON like array of objects please dont do any modification in the returned string

console.log(JSON.parse(data));

＆＃13;

解析转义的javascript

4 个答案: