Question

我想阅读一个文件，其中每一行代表一个包含日期，一些文本和数字的数据集。例如：

Fri Dec 11 12:40:01 CET 2015    Uptime: 108491  Threads: 2  Questions: 576603  Slow queries: 10  Opens: 2238  Flush tables: 1  Open tables: 7  Queries per second avg: 5.314
Fri Dec 11 12:50:01 CET 2015    Uptime: 109090  Threads: 2  Questions: 580407  Slow queries: 10  Opens: 2253  Flush tables: 1  Open tables: 6  Queries per second avg: 5.320
Fri Dec 11 13:00:01 CET 2015    Uptime: 109690  Threads: 2  Questions: 583895  Slow queries: 10  Opens: 2268  Flush tables: 1  Open tables: 8  Queries per second avg: 5.323
Fri Dec 11 13:10:01 CET 2015    Uptime: 110290  Threads: 1  Questions: 586891  Slow queries: 10  Opens: 2279  Flush tables: 1  Open tables: 6  Queries per second avg: 5.321
Fri Dec 11 13:20:01 CET 2015    Uptime: 110890  Threads: 2  Questions: 590871  Slow queries: 10  Opens: 2292  Flush tables: 1  Open tables: 5  Queries per second avg: 5.328

没有常规分隔字符（如CSV格式），但格式可以很好地描述，因为可以使用制表符，字符和文本。

%DATESTRING%\tUptime: %uptime%  Threads: %threads%  Questions: %questions%  Slow queries: %slow%  Opens: %opens%  Flush tables: %flush%  Open tables: %otables%  Queries per second avg: %qps%

是否有一个函数可以获取格式和文件的描述，并使用给定的数据填充data.frame。？

Answer 1

软件包tidyr有一些实用功能可能对此有用，但如果为此工作构建了更多专用工具，我不会感到惊讶。

我们首先加载数据，在本例中是从字符串

raw <- 'Fri Dec 11 12:40:01 CET 2015    Uptime: 108491  Threads: 2     Questions: 576603  Slow queries: 10  Opens: 2238  Flush tables: 1  Open tables: 7  Queries per second avg: 5.314
Fri Dec 11 12:50:01 CET 2015    Uptime: 109090  Threads: 2  Questions: 580407  Slow queries: 10  Opens: 2253  Flush tables: 1  Open tables: 6  Queries per second avg: 5.320
Fri Dec 11 13:00:01 CET 2015    Uptime: 109690  Threads: 2  Questions: 583895  Slow queries: 10  Opens: 2268  Flush tables: 1  Open tables: 8  Queries per second avg: 5.323
Fri Dec 11 13:10:01 CET 2015    Uptime: 110290  Threads: 1  Questions: 586891  Slow queries: 10  Opens: 2279  Flush tables: 1  Open tables: 6  Queries per second avg: 5.321
Fri Dec 11 13:20:01 CET 2015    Uptime: 110890  Threads: 2  Questions: 590871  Slow queries: 10  Opens: 2292  Flush tables: 1  Open tables: 5  Queries per second avg: 5.328'

df <- read.csv(textConnection(raw), header=F)

我已使用read.csv这样我将其作为数据框使用，但您也可以使用readLines并自行将其添加到框架中。

然后我们处理它

library(tidyr)
> processed <- df %>% extract(V1,
  c("Date", "Uptime", "Threads", "Questions"),
  "(.*) *Uptime: (\\d+) *Threads: (\\d+) *Questions: (\\d+)")
> processed
                              Date Uptime Threads Questions
1 Fri Dec 11 12:40:01 CET 2015     108491       2    576603
2 Fri Dec 11 12:50:01 CET 2015     109090       2    580407
3 Fri Dec 11 13:00:01 CET 2015     109690       2    583895
4 Fri Dec 11 13:10:01 CET 2015     110290       1    586891
5 Fri Dec 11 13:20:01 CET 2015     110890       2    590871

应该清楚如何从这里提取剩余的列。

Answer 2

还有两个选择：

txt <- "Fri Dec 11 12:40:01 CET 2015    Uptime: 108491  Threads: 2  Questions: 576603  Slow queries: 10  Opens: 2238  Flush tables: 1  Open tables: 7  Queries per second avg: 5.314
Fri Dec 11 12:50:01 CET 2015    Uptime: 109090  Threads: 2  Questions: 580407  Slow queries: 10  Opens: 2253  Flush tables: 1  Open tables: 6  Queries per second avg: 5.320
Fri Dec 11 13:00:01 CET 2015    Uptime: 109690  Threads: 2  Questions: 583895  Slow queries: 10  Opens: 2268  Flush tables: 1  Open tables: 8  Queries per second avg: 5.323
Fri Dec 11 13:10:01 CET 2015    Uptime: 110290  Threads: 1  Questions: 586891  Slow queries: 10  Opens: 2279  Flush tables: 1  Open tables: 6  Queries per second avg: 5.321
Fri Dec 11 13:20:01 CET 2015    Uptime: 110890  Threads: 2  Questions: 590871  Slow queries: 10  Opens: 2292  Flush tables: 1  Open tables: 5  Queries per second avg: 5.328"

## first just tack on the date label
txt <- gsub('^', 'Date: ', readLines(textConnection(txt)))

选项1

sp <- strsplit(txt, '\\s{2,}')
out <- lapply(sp, function(x) gsub('([\\w ]+:)\\s+(.*)$', '\\2', x, perl = TRUE))
dd <- setNames(do.call('rbind.data.frame', out),
               gsub('([\\w ]+):\\s+(.*)$', '\\1', sp[[1]], perl = TRUE))
dd[, -1] <- lapply(dd[, -1], function(x) as.numeric(as.character(x)))
dd

选项2：此选项使用yaml包，但更直接，并为您进行类型转换

yml <- gsub('\\s{2,}', '\n', txt)
do.call('rbind.data.frame', lapply(yml, yaml::yaml.load))

#                    Date Uptime Threads Questions Slow queries Opens Flush tables
# 1 Fri Dec 11 12:40:01 CET 2015 108491       2    576603           10  2238            1
# 2 Fri Dec 11 12:50:01 CET 2015 109090       2    580407           10  2253            1
# 3 Fri Dec 11 13:00:01 CET 2015 109690       2    583895           10  2268            1
# 4 Fri Dec 11 13:10:01 CET 2015 110290       1    586891           10  2279            1
# 5 Fri Dec 11 13:20:01 CET 2015 110890       2    590871           10  2292            1
#   Open tables Queries per second avg
# 1           7                  5.314
# 2           6                  5.320
# 3           8                  5.323
# 4           6                  5.321
# 5           5                  5.328

如何在R中读取具有特定格式的文件？

2 个答案: