Question

我的PHP分页有一个小问题，我有6条记录，我一次显示2条，当我点击下一条，它显示2到4条记录，工作正常，但显示从4到6记录，这不起作用。我不确定我做错了什么。有人有主意吗？问题是要对要显示的下一条记录进行计算

<?php
$per_page = 2;
$start = $_GET['start'];
$query = mysql_query("SELECT * FROM Directory");
$record_count = mysql_num_rows($query);
$record_count = round($record_count / $per_page);

if(!$start) {
    $start = 0;
}

$query = mysql_query("SELECT * FROM Directory LIMIT $start,$per_page") or     die(mysql_error());
$row = mysql_num_rows($query);
// Output Records here

// Setup next and previous button variables
$prev = $start - $per_page;
$next = $start + $per_page;

echo '<p> <h4>';
if($prev < 0) {
    echo 'Previous';
} else {
    echo '<a href="directory.php?start='.$prev.'>Previous</a>';
}

echo ' ' . $start . ' of ' . $record_count;

if($next < $record_count) {
    echo ' <a href="directory.php?start='.$next.'>Next</a>';
} else {
    echo ' Next';
}
echo '</h4> </p>';
?>

Answer 1

看起来这是格式化问题。当我查看您的来源网址http://gebsbo.limewebs.com/directory/directory.php?start=1时，我看到了：

<br /><p> <h4>Previous 1 of 4 <a href="directory.php?start=3>Next</a></h4> </p> </body>

看起来你错过了href属性的引用。

在您的代码中，您需要：

echo '<a href="directory.php?start='.$prev.'">Previous</a>';

和

echo ' <a href="directory.php?start='.$next.'">Next</a>';

Answer 2

使用此代码进行计算：

$num = 10; // number of items on page
$p = $_GET['page']; // the var that comes from url (for ex: htttp://..../xxx.php?page=3)
$r = mysql_query(" select * from your_table ");

$posts=mysql_num_rows($r); // total posts
$total=(($posts-1)/$num)+1; // toatal pages
$total=intval($total);
$p=intval($p);
if(empty($p) or $p<0 or !isset($p)) $p=1;
if($p>$total) $p=$total;
$start=$p*$num-$num;

// here print the html for pagination (for ex: htttp://...../xxx.php?page=1 .. 2 ...3 .... and so on ...) you can make a for() here

$r = mysql_query(" select * from your_table limit ".$start.", ".$num);
while (....) {
.....
}

小问题PHP分页数学帮助

2 个答案: