Question

我创建了分页并且它目前正在运行，但唯一的问题是如果我有成千上万的结果......显示将是：

[1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15] [16 ] [17] [18]等等。

我只想让显示的页面看起来与此类似：

之前[1] [2] [3] [4] [5] ......下一个

之前...... [5] [6] [7] [8] [9] [10] ......下一个

任何人都可以提供建议或提供一些示例代码，可以给我一个像上面这样的结果吗？如果有什么不清楚的地方请告诉我！

干杯，

尼尔

我目前使用的代码如下：

<?php
/*data base connection */

include "datebase connection";

/* SQL query */

$tsql = ("  SELECT   TOP 100  tie_parent_id, CAST(geo_post AS varchar(6)) + '.' + CAST(geo_sample AS varchar(6)) AS Mile, gps_lat, gps_long, rotten, split, wheel_cut, broken, quality
FROM  database
");

$stmt = sqlsrv_query($conn,$tsql, array(), array( "Scrollable" => 'static'));
if( $stmt === false)
{
     echo "Error in query preparation/execution.\n";
     die( print_r( sqlsrv_errors(), true));
}

/* DETERMINING THE NUMBER OF ROWS (AND PAGES) */

// Set the number of rows to be returned on a page. 
$rowsPerPage = 10;

// Get the total number of rows returned by the query.  
$rowsReturned = sqlsrv_num_rows($stmt);


if($rowsReturned === false) 
    die( print_r( sqlsrv_errors(), true)); 
elseif($rowsReturned == 0) 
{ 
    echo "No rows returned."; 
    exit(); 
} 
else 
{     
    /* Calculate number of pages. */ 
    $numOfPages = ceil($rowsReturned/$rowsPerPage); 
}


/* FUNCTION FOR PAGING */



function getPage($stmt, $pageNum, $rowsPerPage ) 
{ 
    $offset = ($pageNum - 1) * $rowsPerPage; 
    $rows = array(); 
    $i = 0; 
    while($row = sqlsrv_fetch_array($stmt, 
                                    SQLSRV_FETCH_NUMERIC, 
                                    SQLSRV_SCROLL_ABSOLUTE, 
                                    $offset + $i) 
           && $i < $rowsPerPage) 
    { 
        array_push($rows, $row); 
        $i++; 
    } 
    $row = sqlsrv_fetch_array($stmt,SQLSRV_FETCH_NUMERIC,SQLSRV_SCROLL_ABSOLUTE, $offset -1);
    return $rows; 
}


// Display the selected page of data. 
echo "<table width='800' border='0'>";
echo "<tr> <th>Tie ID</th> <th>Mile/Yard</th> <th>GPS Lat</th><th>GPS Long</th><th>Rotten</th><th>Split</th><th>WheelCut</th> <th>Broken</th><th>Quality</th> </tr>";
// keeps getting the next row until there are no more to get
$pageNum = isset($_GET['pageNum']) ? $_GET['pageNum'] : 1; 
$page = getPage($stmt, $pageNum, $rowsPerPage);


$color1 = "#ffffff"; 
$color2 = "#edf5fa"; 
$row_count = "0";



while($row_count<10 ) {

$row=sqlsrv_fetch_array($stmt);
$tie_parent_id = $row["tie_parent_id"];
$geo_post = $row["Mile"];
$lat =$row["gps_lat"];
$long =$row["gps_long"];
$rotten =$row["rotten"];
$split =$row["split"];
$wheelcut =$row["wheel_cut"];
$broken =$row["broken"];
$quality =$row["quality"];

$row_color = ($row_count % 2) ? $color1 : $color2; 


?>

<tr> 

<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["tie_parent_id"]; ?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["Mile"];?> </td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["gps_lat"];?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["gps_long"];?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["rotten"];?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["split"];?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["wheel_cut"];?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["broken"];?></td>
<td bgcolor="<?php echo $row_color ?>">
<?php echo $row["quality"];?></td>
</td></tr>


<?php
    $row_count++; 
}
?>


<?php
/* PREVIOUS PAGE NAVIGATION TOP OF PAGE */

// Display Previous Page link if applicable. 
if($pageNum > 1) 
{ 
    $prevPageLink = "?pageNum=".($pageNum - 1); 
    echo "<a href='$prevPageLink'>Previous Page</a>&nbsp"; 
}

/*DISPLAYING LINKS TO PAGES TOP OF PAGE*/
for($i = 1; $i<=$numOfPages; $i++)  
{  
    $pageLink = "?pageNum=$i";  
    print("<a href=$pageLink>$i</a>&nbsp;&nbsp;");  
}

/* NEXT PAGE NAVIGATION TOP OF PAGE */


// Display Next Page link if applicable. 
if($pageNum < $numOfPages) 
{ 
    $nextPageLink = "?pageNum=".($pageNum + 1); 
    echo "&nbsp;&nbsp;<a href='$nextPageLink'>Next Page</a>"; 
}
?>
</form>
<?php

/* Close the connection. */
sqlsrv_close( $conn);

?>

Answer 1

这种变化实际上并不太疯狂 - 你拥有大部分内容。你的算法需要稍微改变一下页面的显示 - 所以不要像你一样运行你的循环：


/*DISPLAYING LINKS TO PAGES TOP OF PAGE*/
for($i = 1; $i<=$numOfPages; $i++)  
{      
     $pageLink = "?pageNum=$i";      
     print("$i  ");  
}

您需要从您当前的页码开始......


/*first check to make sure the number of pages don't exceed maximum*/
$totalPagesToLoop = $pageNum + $numOfPages;
if($totalPagesToLoop > ceiling(total number of pages required to show all the records ([number of total rows]/[number of rows to show per page])
{
     $totalPagesToLoop = ceiling(total number of pages required to show all the records ([number of total rows]/[number of rows to show per page]);
}



/*DISPLAYING LINKS TO PAGES TOP OF PAGE*/
for($i = $pageNum; $i<=$totalPagesToLoop; $i++)  
{      
     $pageLink = "?pageNum=$i";      
     print("$i  ");  
}

但是 - 不是全部，你现在必须编写特殊的'上一个'和'下一个'按钮（你决定点击它时增加多少 - 谷歌增加1，直到它达到20，然后只是一次显示20个，一个接一个地移动。你必须测试你的变量来决定是否要显示“上一个”或“下一个”按钮......

Answer 2

我设法使用以下代码解决了这个问题：

for($i = $pageNum; $i<=$numOfPages&&$pagesadded<=9; $i++)  
{  
    $pagesadded+=1;
    $pageLink = "?pageNum=$i";  
    print("<a href=$pageLink>$i</a>&nbsp;&nbsp;");  
}

一次显示10页。

干杯，

尼尔

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2 个答案: