Question

我正在使用Jersey javax Web服务实现Web服务。我从Postman休息客户端发送json对象到我的Web服务，但我无法在我的Web服务中处理该json。

@POST
    @Path("/login")
    @Consumes(MediaType.APPLICATION_JSON)
    @Produces(MediaType.APPLICATION_JSON)
    public Person login(Person person) throws ClassNotFoundException, SQLException { 
    Person todo = new Person();
        todo.setValid_user(true);
        return todo;
    }

我正在从邮递员休息客户端发送json到上面的函数，如下所示。

http://localhost:8080/RestWebService/rest/person/login

原始我正在写我的json输入

{"Person":[
"valid_user":"true"
"userId":"1",
"UserName":"parag",
"userPassword":"parag123",
"userLocation":"asd",
"userTime":"asda",
"message":"asdasd"
]}

但我得到500和415错误。请帮帮我。

人员类：

package com.avilyne.rest.model;

import javax.xml.bind.annotation.XmlRootElement;

import org.codehaus.jackson.annotate.JsonIgnore; import org.codehaus.jackson.annotate.JsonProperty;

@XmlRootElement
public class Person {
    @JsonProperty("userId")
    private String userId;
    @JsonProperty("UserName")
    private String UserName;
    @JsonProperty("userPassword")
    private String userPassword;
    @JsonProperty("userLocation")
    private String userLocation;
    @JsonProperty("userTime")
    private String userTime;
    @JsonProperty("message")
    private String message;
    @JsonProperty("valid_user")
    private String valid_user;




     public String isValid_user() {
        return valid_user;
    }
     public void setValid_user(String valid_user) {
        this.valid_user = valid_user;
    }
     public String getMessage() {
        return message;
    }
     public void setMessage(String message) {
        this.message = message;
    }
     public String getUserId() {
        return userId;
    }
     public void setUserId(String userId) {
        this.userId = userId;
    }
     public String getUserName() {
        return UserName;
    }
     public void setUserName(String userName) {
        UserName = userName;
    }
     public String getUserPassword() {
        return userPassword;
    }
     public void setUserPassword(String userPassword) {
        this.userPassword = userPassword;
    }
     public String getUserLocation() {
        return userLocation;
    }
     public void setUserLocation(String userLocation) {
        this.userLocation = userLocation;
    }
     public String getUserTime() {
        return userTime;
    }
     public void setUserTime(String userTime) {
        this.userTime = userTime;
    }
    @Override
     public String toString() {
        return "Person [userId=" + userId + ", UserName=" + UserName + ", userPassword=" + userPassword
                + ", userLocation=" + userLocation + ", userTime=" + userTime + "]";
    }        
}

Answer 1

使用杰克逊映射器，它会自动将json转换为你的“人物”。对象，反之亦然。

您只需更新您的“人物”即可。 bean并添加@JsonProperty和@JsonCreator注释（通过下面的链接），杰克逊将负责其余的工作。

https://github.com/FasterXML/jackson-annotations

有效的json应该是： { "valid_user":"true", "userId":"1", "userName":"parag", "userPassword":"parag123", "userLocation":"asd", "userTime":"asda", "message":"asdasd" }

编辑：



import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonProperty;

public class Person {

    @JsonProperty("userId")
    private String userId;

    @JsonProperty("userName")
    private String userName;

    @JsonProperty("userPassword")
    private String userPassword;

    @JsonProperty("userLocation")
    private String userLocation;

    @JsonProperty("userTime")
    private String userTime;

    @JsonProperty("message")
    private String message;

    @JsonProperty("valid_user")
    private boolean valid_user;

    @JsonCreator
    public Person(@JsonProperty("userId") String userId,
                  @JsonProperty("userName") String userName,
                  @JsonProperty("userPassword") String userPassword,
                  @JsonProperty("userLocation") String userLocation,
                  @JsonProperty("userTime") String userTime,
                  @JsonProperty("message") String message,
                  @JsonProperty("valid_user") boolean valid_user) {
        this.userId = userId;
        this.userName = userName;
        this.userPassword = userPassword;
        this.userLocation = userLocation;
        this.userTime = userTime;
        this.message = message;
        this.valid_user = valid_user;
    }

    public String getUserId() {
        return userId;
    }

    public String getUserName() {
        return userName;
    }

    public String getUserPassword() {
        return userPassword;
    }

    public String getUserLocation() {
        return userLocation;
    }

    public String getUserTime() {
        return userTime;
    }

    public String getMessage() {
        return message;
    }

    public boolean isValid_user() {
        return valid_user;
    }

    @Override
    public String toString() {
        return "Person{" +
                "userId='" + userId + '\'' +
                ", userName='" + userName + '\'' +
                ", userPassword='" + userPassword + '\'' +
                ", userLocation='" + userLocation + '\'' +
                ", userTime='" + userTime + '\'' +
                ", message='" + message + '\'' +
                ", valid_user=" + valid_user +
                '}';
    }
}

import com.fasterxml.jackson.annotation.JsonCreator; import com.fasterxml.jackson.annotation.JsonProperty; public class Person { @JsonProperty("userId") private String userId; @JsonProperty("userName") private String userName; @JsonProperty("userPassword") private String userPassword; @JsonProperty("userLocation") private String userLocation; @JsonProperty("userTime") private String userTime; @JsonProperty("message") private String message; @JsonProperty("valid_user") private boolean valid_user; @JsonCreator public Person(@JsonProperty("userId") String userId, @JsonProperty("userName") String userName, @JsonProperty("userPassword") String userPassword, @JsonProperty("userLocation") String userLocation, @JsonProperty("userTime") String userTime, @JsonProperty("message") String message, @JsonProperty("valid_user") boolean valid_user) { this.userId = userId; this.userName = userName; this.userPassword = userPassword; this.userLocation = userLocation; this.userTime = userTime; this.message = message; this.valid_user = valid_user; } public String getUserId() { return userId; } public String getUserName() { return userName; } public String getUserPassword() { return userPassword; } public String getUserLocation() { return userLocation; } public String getUserTime() { return userTime; } public String getMessage() { return message; } public boolean isValid_user() { return valid_user; } @Override public String toString() { return "Person{" + "userId='" + userId + '\'' + ", userName='" + userName + '\'' + ", userPassword='" + userPassword + '\'' + ", userLocation='" + userLocation + '\'' + ", userTime='" + userTime + '\'' + ", message='" + message + '\'' + ", valid_user=" + valid_user + '}'; } }

我更新了上面的json，你错过了＆＃39;，＆＃39;在valid_user之后我也改变了＃34; UserName＆＃34; to＆＃34; userName＆＃34; （如果你愿意，可以改变它）。

请测试一下，让我知道它是否有效。

Answer 2

您的JSON 无效（使用JSONLint检查）：

您服务中使用的有效JSON将是：

{
    "valid_user": true,
    "userId": "1",
    "UserName": "parag",
    "userPassword": "parag123",
    "userLocation": "asd",
    "userTime": "asda",
    "message": "asdasd"
}

请注意,和"valid_user":"true"之后的{}而不是[]。

您不需要{ "Person": {...} }。

如何处理来自android端的

2 个答案: