Question

我必须编写一个程序，要求用户输入一个整数值。在每个值之后，如果用户想要继续该程序，则用户必须以“y”或“n”作出响应，并且用户输入的每个数字被表示为奇数或偶数。

到目前为止，我已经使用do-while循环完成了这项工作，但我对如何获取用户输入的值的平均值感到困惑。您如何获得所有输入数字的平均值？

到目前为止，这是我的代码：

import java.util.Scanner;
class ProgramTest {
    public static void main(String[] args) {
        String answer = "";

        do {

            int num, count = 0;
            Scanner scan = new Scanner(System. in );
            System.out.print("Enter any number : ");
            num = scan.nextInt();

            if ((num % 2) == 0) System.out.println(num + " is an even number.");
            else System.out.println(num + " is an odd number");
            System.out.println("do you want to continue?");
            answer = scan.next();
            count++;

        } while (answer.equals("y"));

    }
}

Answer 1

从问题看起来需要处理以下事项，

没有添加添加机制到单个变量。

将所有变量放入do ... while循环体......

根据要求创建了附加变量。

使用以下代码段查看我所涵盖的所有内容。

同样做点什么，

String answer = "";
double sum = 0; // use for storing addition to all entered values..
int num, count = 0;
 Scanner scan = new Scanner(System.in);

        do {
            System.out.print("Enter any number : ");
            num = scan.nextInt(); // getting input from user through console
            sum = sum + num; // add every input number into sum-variable
            if ((num % 2) == 0) System.out.println(num + " is an even number.");
            else System.out.println(num + " is an odd number");
            System.out.println("do you want to continue?");
            answer = scan.next(); // ask for still want to repeat..
            count++;

        } while (answer.equals("y"));
System.out.println("Average is : " + sum + "/" + count + " = "+ (sum /count));

Answer 2

为了计算平均值，您需要两件事：所有数字的总和和平均值计算中涉及的所有数字的计数。

参与平均值计算的orders.orderitem_set.all和sum需要超出count范围才能在计算中已知阶段。

我也冒昧地修改你的代码

do..while

Answer 3

更改您的代码：

  import java.util.Scanner;
    class ProgramTest {
        public static void main(String[] args) {
            String answer = "";
            int avr =0;
            int num, count = 0;
            do {

                Scanner scan = new Scanner(System. in );
                System.out.print("Enter any number : ");
                num = scan.nextInt();

                if ((num % 2) == 0) System.out.println(num + " is an even number.");
                else System.out.println(num + " is an odd number");
                System.out.println("do you want to continue?");
                avr += num;
                answer = scan.next();
                count++;

            } while (answer.equals("y"));
           avr = avr /count;
     System.out.println("The avreage of value is:" + avr );
        }
    }

avr是平均值。这意味着当你输入一个整数。我们添加num和avr。并完成循环。我们分数。像这样：

1-5-9-11

avr = 1 + 5 + 9 + 11;

count = 4;

avr = avr / 4;

如何在do-while循环中找到平均值

3 个答案: