Question

我需要从dict中的特定键中删除重复值例如

我有

data = [{'NAME':'John','AGE':23,'NUMBER':345},
        {'NAME':'Michel','AGE':23,'NUMBER':346},
        {'NAME':'RAHUL','AGE':23,'NUMBER':347},
        {'NAME':'Susea','AGE':23,'NUMBER':346},
        {'NAME':'Wincent','AGE':23,'NUMBER':342}]

在上面我需要将'NUMBER'键唯一唯一注意：{'NUMBER'：346}出现2次。我需要输出

data = [{'NAME':'John','AGE':23,'NUMBER':'345'},
        {'NAME':'Michel','AGE':23,'NUMBER':346},
        {'NAME':'RAHUL','AGE':23,'NUMBER':347},
        {'NAME':'Wincent','AGE':23,'NUMBER':342}]

（即）删除特定密钥副本的任何重复记录

请帮助我

Answer 1

这样的事情：

data = [{'NAME':'John','AGE':23,'NUMBER':345},
        {'NAME':'Michel','AGE':23,'NUMBER':346},
        {'NAME':'RAHUL','AGE':23,'NUMBER':347},
        {'NAME':'Susea','AGE':23,'NUMBER':346},
        {'NAME':'Wincent','AGE':23,'NUMBER':342}]

filtered_data = []
seen = set()
for item in data:
    number = item['NUMBER']
    if number not in seen:
        filtered_data.append(item)
        seen.add(number)
# filtered_data is deduped

Answer 2

这有效：

key = 'NUMBER'
seen = set()
res = []
for entry in data:
    if not entry[key] in seen:
        res.append(entry)
        seen.add(entry[key])

结果：

>>> res
[{'AGE': 23, 'NAME': 'John', 'NUMBER': 345},
 {'AGE': 23, 'NAME': 'Michel', 'NUMBER': 346},
 {'AGE': 23, 'NAME': 'RAHUL', 'NUMBER': 347},
 {'AGE': 23, 'NAME': 'Wincent', 'NUMBER': 342}]

使用set保存已经看到的值。对于大型列表，这比使用val in seen_list之类的列表更有效。

Answer 3

创建唯一的数字列表。

<强> ALGO ：

uni_no是唯一的号码列表。
data1过滤进程的最终输出。
data为loop

NUMBER

检查data1是否存在迭代项。
如果没有，请添加到uni_no并将号码添加到>>> data = [{'NAME':'John','AGE':23,'NUMBER':345}, ... {'NAME':'Michel','AGE':23,'NUMBER':346}, ... {'NAME':'RAHUL','AGE':23,'NUMBER':347}, ... {'NAME':'Susea','AGE':23,'NUMBER':346}, ... {'NAME':'Wincent','AGE':23,'NUMBER':342}] >>> >>> data [{'AGE': 23, 'NAME': 'John', 'NUMBER': 345}, {'AGE': 23, 'NAME': 'Michel', 'NUMBER': 346}, {'AGE': 23, 'NAME': 'RAHUL', 'NUMBER': 347}, {'AGE': 23, 'NAME': 'Susea', 'NUMBER': 346}, {'AGE': 23, 'NAME': 'Wincent', 'NUMBER': 342}] >>> uni_no = [] >>> data1 = [] >>> for i in data: ... if i["NUMBER"] not in uni_no: ... uni_no.append(i["NUMBER"] ) ... data1.append(i) ... >>> data1 [{'AGE': 23, 'NAME': 'John', 'NUMBER': 345}, {'AGE': 23, 'NAME': 'Michel', 'NUMBER': 346}, {'AGE': 23, 'NAME': 'RAHUL', 'NUMBER': 347}, {'AGE': 23, 'NAME': 'Wincent', 'NUMBER': 342}]

<强>演示：

<meta name="google-signin-client_id" content="xxxxxxxx-xxxxxxxx.apps.googleusercontent.com">

<div id="gConnect" style="display:inline-block !important;">
                                <div id="signin-button"></div> 
</div>

//Script

 <script src="https://apis.google.com/js/client:platform.js?onload=startApp" async defer></script>
    <script type="text/javascript">

            var auth2 = {};
            var helper = (function () {
                return {
                    /**
                     * Hides the sign in button and starts the post-authorization operations.
                     *
                     * param {Object} authResult An Object which contains the access token and
                     *   other authentication information.
                     */
                    onSignInCallback: function (authResult) {
                        if (authResult.isSignedIn.get()) {
                            helper.profile();
                        } else if (authResult['error'] || authResult.currentUser.get().getAuthResponse() == null) {
                            console.log('There was an error: ' + authResult['error']);
                            $('#gConnect').show();
                        }
                    },

                    /**
                     * Gets and renders the currently signed in user's profile data.
                     */
                    profile: function () {
                        gapi.client.plus.people.get({
                            'userId': 'me'
                        }).then(function (res) {
                            var profile = res.result;
                            var EmailId = profile.emails[0].value;
                            var FullName = res.result.name.givenName;
                            var auth2 = gapi.auth2.getAuthInstance();
                            auth2.signOut().then(function () { });

                            linkedinData=res;
                            flag="G";

                            $.post('@Url.Action("CheckEmailLogin","Home")',{Email:EmailId,type:flag},function(data){
                                if(data.msg=="Already registred.")
                                {
                                    window.location.href = '@Url.Action("SocialLogin", "Home")' + '?UserEMailId=' + EmailId + '&FirstName=' + FullName + '&type=G&UserType='+$("#ddlUserType").val()+'';
                                }
                                else if(data.msg=="Not register");
                                {
                                    $("#DvUserType").modal('show');
                                }
                                if(data.msg=="Email is exist.")
                                {
                                    alert("Email is already registered.");
                                }
                            });
                        }, function (err) {
                            var error = err.result;
                            console.log(erroe);
                            $('#gConnect').show();
                        });
                    }
                };
            })();

            /**
        * Handler for when the sign-in state changes.
        *
        * param {boolean} isSignedIn The new signed in state.
        */
            var updateSignIn = function () {
                if (auth2.isSignedIn.get()) {
                    helper.onSignInCallback(gapi.auth2.getAuthInstance());
                } else {
                    helper.onSignInCallback(gapi.auth2.getAuthInstance());
                }
            }

            /**
             * This method sets up the sign-in listener after the client library loads.
             */
            function startApp() {
                gapi.load('auth2', function () {
                    gapi.client.load('plus', 'v1').then(function () {
                        gapi.signin2.render('signin-button', {
                            scope: 'https://www.googleapis.com/auth/plus.login',
                            fetch_basic_profile: true
                        });
                        gapi.auth2.init({
                            fetch_basic_profile: true,
                            scope: 'https://www.googleapis.com/auth/userinfo.email'
                        }).then(
                              function () {
                                  auth2 = gapi.auth2.getAuthInstance();
                                  auth2.isSignedIn.listen(updateSignIn);
                                  auth2.then(updateSignIn());
                              });
                    });
                });
            }

Answer 4

以下是一些步骤： 1.为您的found_numbers创建一个空列表。 2.迭代所有字典条目。 3.对于每个字典，查看数字键的值是否在您的found_numbers列表中。如果该号码存在，则这是重复的条目。您可以从列表中删除它否则找不到这个数字，所以这是带有这个数字的字典的第一个实例。我们需要将此数字添加到found_numbers列表中。

注意：这假定先到先得的态度对待重复的条目。

从Python中的特定字典键的值中删除重复项

4 个答案: