Question

如果特定键值（即键：x['src_ip']）多次出现，我将如何在Python中重复删除字典列表？

x = [{"_serial": "0", "src_ip": "5.5.5.5"}, 
     {"_serial": "1", "src_ip": "5.5.5.5"},
     {"_serial": "2", "src_ip": "1.1.1.2"}, 
     {"_serial": "3", "src_ip": "1.2.6.4"}]

我基本上希望将以下列表作为最终结果：

x = [{"_serial": "0", "src_ip": "5.5.5.5"},
     {"_serial": "2", "src_ip": "1.1.1.2"},
     {"_serial": "3", "src_ip": "1.2.6.4"}]

Answer 1

您可以使用itertools.groupby()和next()来实现此目标：

from itertools import groupby

result = [next(v) for k, v in groupby(x, lambda d: d["src_ip"])]

<强> result ：

[{'_serial': '0', 'src_ip': '5.5.5.5'},
 {'_serial': '2', 'src_ip': '1.1.1.2'},
 {'_serial': '3', 'src_ip': '1.2.6.4'}]

原样，仅当您的列表已在d["src_ip"]上排序时，此功能才有效。如果没有，请先排序：

def key(d):
    return d["src_ip"]

result = [next(v) for k, v in groupby(sorted(x, key=key), key)]

Answer 2

对于此特定输入和所需输出，您可以尝试：

x = [{"_serial": "0", "src_ip": "5.5.5.5"}, 
 {"_serial": "1", "src_ip": "5.5.5.5"},
 {"_serial": "2", "src_ip": "1.1.1.2"}, 
 {"_serial": "3", "src_ip": "1.2.6.4"}]

values = []
new_x = []

for d in x:
    if not d['src_ip'] in values:
        new_x.append(d)
        values.append(d['src_ip'])

print(new_x)

如果key，value存在，则删除重复的字典列表＆gt; 1

2 个答案: