Question

这是一个简单的字谜游戏代码：

#define NP 5
#define LP 10
void anagrammi() {
    srand(time (NULL));
    char words[NP][LP] = {"cane", "gatto", "gallo", "rana", "ibis"};
    typedef struct { 
    char parola[LP];
    int usati[LP];
    char anagramma[LP];
    }an ;
int a, len, i, j, cont;
char merda[LP], c;
an yoda;

a = rand()%5;
strcpy(yoda.parola, words[a]);
len = strlen(yoda.parola);
for (i = 0; i < len; i++){
yoda.usati[i] = len+2;
}
i = 0;
while (i < len){
    cont = 0;
    a = rand()%len;
    for (j = 0; j < len; j++){
if (a == yoda.usati[j]) cont++; 
} if (cont == 0) { 
yoda.usati[i] = a;
yoda.anagramma[i] = yoda.parola[a];
i++;
}
}
j = 0;
cont = 0;
yoda.anagramma[i] = '\0';
printf("Anagramma di %s ? ", yoda.anagramma);
c = getchar() ;
while( c != '\n' && j < LP ){
merda[j] = c ;
j++ ;
c = getchar(); }
merda[j] = '\0';
for (i = 0; i < len; i++){
    if (merda[i] =! yoda.parola[i]) cont++;
    printf("\n%d", cont);
    printf("\n%c", merda[i]);
    printf("\n%c", yoda.parola[i]);
} 
if (cont =! 0) printf("\nFALSE");
else printf ("\nTRUE");
}

程序继续，但是当我插入单词并将其与原始单词进行比较时，即使我输入了正确的单词，最终输出也始终为FALSE。问题也发生在没有\ 0.任何人都可以帮助我吗？

感谢答案，这是一个完美的工作程序：

void anagrammi() {
    srand(time (NULL));
    char words[NP][LP] = {"cane", "gatto", "gallo", "rana", "ibis"};
    typedef struct { 
    char parola[LP];
    int usati[LP];
    char anagramma[LP];
    }an ;
int a, len, i, j, cont;
char merda[LP], c;
an yoda;

a = rand()%5;
strcpy(yoda.parola, words[a]);
len = strlen(yoda.parola);
for (i = 0; i < len; i++){
yoda.usati[i] = len+2;
}
i = 0;
while (i < len){
    cont = 0;
    a = rand()%len;
    for (j = 0; j < len; j++){
if (a == yoda.usati[j]) cont++; 
} if (cont == 0) { 
yoda.usati[i] = a;
yoda.anagramma[i] = yoda.parola[a];
i++;
}
}
j = 0;
cont = 0;
yoda.anagramma[i] = '\0';
printf("Anagramma di %s ? ", yoda.anagramma);
c = getchar() ;
while( c != '\n' && j < LP ){
merda[j] = c ;
j++ ;
c = getchar(); }
for (i = 0; i < len; i++){
    if (merda[i] != yoda.parola[i]) cont++;

} 
i = strlen(merda);
if (cont != 0 || i > len ) printf("\nNON HAI INDOVINATO");
else printf ("\nHAI INDOVINATO");

}

Answer 1

应该是(cont =! 0)的

(cont != 0) - kaylum

获得字符串c

1 个答案: