人。 马上抱歉我的英语。 我需要帮助解决我自己几天无法决定的问题。
我有一个与mongoDB相关的C#项目。 用户可以创建一个帐户并为他创建两个字符。
这里是角色创作:
Character.Character character = new Character.Character
{
SocialClubName = player.socialClubName,
Name = name,
Surname = surname,
RegistrationDate = DateTime.Now,
LastLoginDate = DateTime.Now,
RegistrationIp = player.address,
CurrentIp = player.address
};
Characters.InsertOneAsync(character);
Character.cs
public class Character
{
[BsonId]
public ObjectId Id { get; set; }
public string SocialClubName { get; set; }
public string Name { get; set; }
public string Surname { get; set; }
public string RegistrationIp { get; set; }
public string CurrentIp { get; set; }
public DateTime RegistrationDate { get; set; }
public DateTime LastLoginDate { get; set; }
}
问题是从数据库中获取这些数据。我需要有两个字符数据的全局变量。
现在看起来像这样:
public static string Name { get; set; }
public static string Surname { get; set; }
public static string RegistrationIp { get; set; }
public static string CurrentIp { get; set; }
public static DateTime RegistrationDate { get; set; }
public static DateTime LastLoginDate { get; set; }
public static async Task LoadCharacterData(Client player)
{
var filter = new BsonDocument("NameOfTable", player.name);
var characters = await DatabaseManager.Characters.Find(filter).ToListAsync();
foreach (var character in characters)
{
Name = character.Name;
Surname = character.Surname;
RegistrationIp = character.RegistrationIp;
CurrentIp = character.CurrentIp;
RegistrationDate = character.RegistrationDate;
LastLoginDate = character.LastLoginDate;
}
}
看起来很愚蠢,因为我刚刚开始使用C#。我决定使用MongoDB,因为我之前使用过MeteorApp。
答案 0 :(得分:0)
每次阅读时,您的示例都会覆盖名称/ SurName等,因此您只会检索最后一个字符。
您可以创建一个User类并获取这些内容,如下所示:
public class User
{
public string Name{get;set;}
public string SurName{get;set;}
}
public static List<User> Users {get;set;}
public static async Task LoadCharacterData(Client player)
{
//*Snip*
foreach(var character in character)
Users.Add(new User {Name = character.Name; SurName = character.Surname;}
}