Question

我有一个包含3个字段ID，A，B的表。我想从某个ID中找到每个A中出现的每个B

例如：

ID  |   A   |   B   |
----------------------
1   |   10  |   22  |
1   |   10  |   24  |
1   |   11  |   22  |
    |       |       |
2   |   12  |   31  |
2   |   13  |   33  |
    |       |       |
3   |   14  |   34  |

应该返回：

ID  |   B   |
-------------
1   |   22  |
3   |   34  |

因为对于来自ID 1的A的每个不同值，发生B = 22。同样适用于身份3。

知道我该怎么办吗？

提前谢谢。

Answer 1

<强> Sql Fiddle Demo

您可以使用此查询来验证您需要的行。

(Key,Field)

但这会提供你想要的结果。

SELECT T1.B, T1.ID, COUNT(DISTINCT A), T2.total_id_a
FROM Table1 T1
JOIN (SELECT ID , COUNT(DISTINCT A) as total_id_a
      FROM Table1
      GROUP BY ID) T2
  ON T1.ID = T2.ID
GROUP BY B, ID;

<强>输出

SELECT ID, B 
FROM (
      SELECT T1.ID, T1.B, COUNT(DISTINCT A), T2.total_id_a
      FROM Table1 T1
      JOIN (SELECT ID , COUNT(DISTINCT A) as total_id_a
            FROM Table1
            GROUP BY ID) T2
        ON T1.ID = T2.ID
      GROUP BY B, ID
      HAVING COUNT(DISTINCT A) = T2.total_id_a
     ) T

Answer 2

# For case ID=1 and B=22 for example above
SELECT DISTINCT t1.ID, t1.B 
FROM yourtable AS t1
INNER JOIN yourtable AS t2 
     ON t2.B = t1.B 
    AND t2.A <> t1.A 
    AND t1.ID = t2.ID

UNION

# For case ID=3 and B=34 for example above
SELECT DISTINCT t1.ID, t1.B 
FROM yourtable AS t1
INNER JOIN yourtable AS t2 
     ON t2.B = t1.B 
    AND t2.A = t1.A 
    AND t1.ID = t2.ID
LEFT JOIN yourtable AS t3
     ON t3.ID = t1.ID
    AND (t3.A <> t1.A OR t3.B <> t1.B)
WHERE t3.ID IS NULL

找到A中每个B中存在的值C.

2 个答案: