我正在尝试解析一个JSON字符串并将其映射到一个hashmap，我有一个来自服务器的有效JSONString但是当我遍历它时，我所能获得的只是第一个结果。
JSONArray peoples = null;
ArrayList<HashMap<String, String>> personList = new ArrayList<HashMap<String,String>>();
JSONObject jsonObj = new JSONObject(value);
Log.d("Jello",jsonObj.toString());
peoples = jsonObj.getJSONArray("product");//check here
Log.d("Jello",peoples.toString());
for(int i=0;i<peoples.length();i++){
JSONObject c = peoples.getJSONObject(i);
String service_group = c.getString("sgroup");
String service = c.getString("service");
String value = c.getString("value");
String updated_at = c.getString("updated_at");
HashMap<String,String> persons = new HashMap<String,String>();
persons.put("service_group",service_group);
persons.put("service",service);
persons.put("value",value);
persons.put("updated_at",updated_at);
personList.add(persons);
}
我的JSON字符串是：
{"product":[{"sgroup":"Dummy_BIG_ONE","service":"Dummy_UNDER_BIG_ONE","code":"128","value":"0","updated_at":"2015-12-04 21:21:00"}]}{"product":[{"sgroup":"Hello Monkey","service":"Do u work","code":"123","value":"0","updated_at":"2015-12-04 21:27:51"}]}{"product":[{"sgroup":"Checking from Android Device","service":"Monkey","code":"12345","value":"0","updated_at":"2015-12-04 22:55:39"}]}{"product":[{"sgroup":"Checking from Android Device","service":"Monkey","code":"12345","value":"0","updated_at":"2015-12-04 22:55:40"}]}{"product":[{"sgroup":"Checking from Android Device","service":"Monkey","code":"12345","value":"0","updated_at":"2015-12-04 22:55:42"}]}{"product":[{"sgroup":"Hello World","service":"Donkey","code":"24411","value":"0","updated_at":"2015-12-04 22:57:05"}]}{"product":[{"sgroup":"lkfnhjdiofho","service":"dfjdifj","code":"1101","value":"0","updated_at":"2015-12-05 01:15:49"}]}{"product":[{"sgroup":"Baal","service":"Saal","code":"1234","value":"21","updated_at":"2015-12-05 01:34:59"}]}{"product":[{"sgroup":"Inis","service":"Mona","code":"1234","value":"1001","updated_at":"2015-12-05 01:39:51"}]}{"product":[{"sgroup":"Medical Treatment Loan","service":"Number of referral slip","code":"128","value":"0","updated_at":"2015-12-05 01:50:42"}]}{"product":[{"sgroup":"Medical Treatment Loan","service":"Number of referral slip","code":"128","value":"0","updated_at":"2015-12-05 01:55:12"}]}{"product":[{"sgroup":"Medical Treatment Loan","service":"Number of referral slip","code":"128","value":"1000","updated_at":"2015-12-05 01:56:10"}]}
或HERE
这是我发送JSON的方式
while($row = mysql_fetch_assoc($output))
{
$product = array();
$product["sgroup"] = $row["service_group"];
$product["service"] = $row["service"];
$product["code"] = $row["code"];
$product["value"] = $row["amount"];
$product["updated_at"] = $row["updated_at"];
// user node
$response["product"] = array();
array_push($response["product"], $product);
// echoing JSON response
echo json_encode($response);
}
我想在我的ArrayList中添加JSON中的所有数据，以便我以后可以使用它。 谢谢你的帮助。
答案 0 :(得分：2)
首先，有online tools可用于确定您的JSON是否有效。
以下是格式化JSON数据的更好方法的一般示例：
<?php
$bigArray = array();
for ($x = 0; $x <= 10; $x++) {
$product = array();
$product["sgroup"] = $x;
$product["service"] = $x;
$product["code"] = $x;
$product["value"] = $x;
$product["updated_at"] = $x;
array_push($bigArray, $product);
}
// echoing JSON response
echo json_encode($bigArray);
?>
这给出了这个简单且易于解析的有效JSON响应：
[
{
"sgroup":0,
"service":0,
"code":0,
"value":0,
"updated_at":0
},
{
"sgroup":1,
"service":1,
"code":1,
"value":1,
"updated_at":1
},
{
"sgroup":2,
"service":2,
"code":2,
"value":2,
"updated_at":2
},
{
"sgroup":3,
"service":3,
"code":3,
"value":3,
"updated_at":3
},
{
"sgroup":4,
"service":4,
"code":4,
"value":4,
"updated_at":4
},
{
"sgroup":5,
"service":5,
"code":5,
"value":5,
"updated_at":5
},
{
"sgroup":6,
"service":6,
"code":6,
"value":6,
"updated_at":6
},
{
"sgroup":7,
"service":7,
"code":7,
"value":7,
"updated_at":7
},
{
"sgroup":8,
"service":8,
"code":8,
"value":8,
"updated_at":8
},
{
"sgroup":9,
"service":9,
"code":9,
"value":9,
"updated_at":9
},
{
"sgroup":10,
"service":10,
"code":10,
"value":10,
"updated_at":10
}
]
至于解析，使用HashMap不是最好的方法。创建Person POJO对象的列表。
首先定义Person类：
class Person {
public String group;
public String service;
public String value;
public String updated;
public Person(String g, String s, String v, String u) {
group = g;
service = s;
value = v;
updated = u;
}
}
然后，解析非常简单：
List<Person> personList = new ArrayList<>();
JSONArray jsonArr;
try {
jsonArr = new JSONArray(response);
for(int i=0;i<jsonArr.length();i++){
JSONObject c = jsonArr.getJSONObject(i);
String service_group = c.getString("sgroup");
String service = c.getString("service");
String value = c.getString("value");
String updated_at = c.getString("updated_at");
Person p = new Person(service_group, service, value, updated_at);
personList.add(p);
}
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
答案 1 :(得分：0)
你应该把你的产品放到json数组中：
[
{
"product": {
"sgroup": "lkfnhjdiofho",
"service": "dfjdifj",
"code": "1101",
"value": "0",
"updated_at": "2015-12-05 01:15:49"
}
},
{
"product": {
"sgroup": "Baal",
"service": "Saal",
"code": "1234",
"value": "21",
"updated_at": "2015-12-05 01:34:59"
}
},
{
"product": {
"sgroup": "Inis",
"service": "Mona",
"code": "1234",
"value": "1001",
"updated_at": "2015-12-05 01:39:51"
}
},
{
"product": {
"sgroup": "Medical Treatment Loan",
"service": "Number of referral slip",
"code": "128",
"value": "0",
"updated_at": "2015-12-05 01:50:42"
}
},
{
"product": {
"sgroup": "Medical Treatment Loan",
"service": "Number of referral slip",
"code": "128",
"value": "0",
"updated_at": "2015-12-05 01:55:12"
}
},
{
"product": {
"sgroup": "Medical Treatment Loan",
"service": "Number of referral slip",
"code": "128",
"value": "1000",
"updated_at": "2015-12-05 01:56:10"
}
}
]
你必须稍微改变你的解析器：
JSONArray jsonArray = new JSONArray(string);
for(int i=0;i<jsonArray.length();i++){
JSONObject c = jsonArray.getJSONObject(i).getJSONObject("product");
String service_group = c.getString("sgroup");
String service = c.getString("service");
String value = c.getString("value");
String updated_at = c.getString("updated_at");
HashMap<String,String> persons = new HashMap<String,String>();
persons.put("service_group",service_group);
persons.put("service",service);
persons.put("value",value);
persons.put("updated_at",updated_at);
personList.add(persons);
}
您不需要将对象放入“product”属性，而是直接放入数组：
[
{
"sgroup": "lkfnhjdiofho",
"service": "dfjdifj",
"code": "1101",
"value": "0",
"updated_at": "2015-12-05 01:15:49"
},
{
"sgroup": "Baal",
"service": "Saal",
"code": "1234",
"value": "21",
"updated_at": "2015-12-05 01:34:59"
},