D3树方向

时间：2015-12-04 18:05:30

标签： javascript d3.js

我正在使用D3树布局，类似于此jsfiddle，唯一的问题是我需要每个节点的方向从布局的左上角开始而不是在顶部中心。

var nodeUpdate = node.transition()
  .duration(duration)
  .attr("transform", function(d) {         
    return "translate(" + d.y + "," + d.x + ")";
});

类似于此的内容：enter image description here

关于如何做到这一点的任何想法？

提前谢谢。

3 个答案:

答案 0 :(得分：1)

建立此example。

// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
    links = tree.links(nodes);

// figure out the placement of the "top-most" node at each depth
var nodeMap = {};
nodes.forEach(function(d) { 
  if (!nodeMap[d.depth] || d.x < nodeMap[d.depth]){
    nodeMap[d.depth] = d.x;
  }
});
// shift all nodes up
nodes.forEach(function(d) { 
  d.y = d.depth * 100;
  d.x -= nodeMap[d.depth];
});

这会产生：

＆＃13;
＆＃13; 
<!DOCTYPE html>
<html lang="en">
  <head>
    <meta charset="utf-8">

    <title>Tree Example</title>

    <style>
	
	.node {
		cursor: pointer;
	}

	.node circle {
	  fill: #fff;
	  stroke: steelblue;
	  stroke-width: 3px;
	}

	.node text {
	  font: 12px sans-serif;
	}

	.link {
	  fill: none;
	  stroke: #ccc;
	  stroke-width: 2px;
	}
	
    </style>

  </head>

  <body>

<!-- load the d3.js library -->	
<script src="http://d3js.org/d3.v3.min.js"></script>
	
<script>

var treeData = [
  {
    "name": "Top Level",
    "parent": "null",
    "children": [
      {
        "name": "Level 2: A",
        "parent": "Top Level",
        "children": [
          {
            "name": "Son of A",
            "parent": "Level 2: A"
          },
          {
            "name": "Daughter of A",
            "parent": "Level 2: A"
          }
        ]
      },
      {
        "name": "Level 2: B",
        "parent": "Top Level",
        "children": [
          {
            "name": "Son of B",
            "parent": "Level 2: B"
          },
          {
            "name": "Daughter of B",
            "parent": "Level 2: B"
          }
        ]
      }
    ]
  }
];


// ************** Generate the tree diagram	 *****************
var margin = {top: 20, right: 120, bottom: 20, left: 120},
	width = 960 - margin.right - margin.left,
	height = 500 - margin.top - margin.bottom;
	
var i = 0,
	duration = 750,
	root;

var tree = d3.layout.tree()
	.size([height, width]);

var diagonal = d3.svg.diagonal()
	.projection(function(d) { return [d.y, d.x]; });

var svg = d3.select("body").append("svg")
	.attr("width", width + margin.right + margin.left)
	.attr("height", height + margin.top + margin.bottom)
  .append("g")
	.attr("transform", "translate(" + margin.left + "," + margin.top + ")");

root = treeData[0];
root.x0 = height / 2;
root.y0 = 0;
  
update(root);

function update(source) {

  // Compute the new tree layout.
  var nodes = tree.nodes(root).reverse(),
	  links = tree.links(nodes);

  // Normalize for fixed-depth.
  var nodeMap = {};
  nodes.forEach(function(d) { 
    if (!nodeMap[d.depth] || d.x < nodeMap[d.depth]){
      nodeMap[d.depth] = d.x;
    }
  });
  nodes.forEach(function(d) { 
    d.y = d.depth * 100;
    d.x -= nodeMap[d.depth];
  });

  // Update the nodes…
  var node = svg.selectAll("g.node")
	  .data(nodes, function(d) { return d.id || (d.id = ++i); });

  // Enter any new nodes at the parent's previous position.
  var nodeEnter = node.enter().append("g")
	  .attr("class", "node")
	  .attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
	  .on("click", click);

  nodeEnter.append("circle")
	  .attr("r", 1e-6)
	  .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

  nodeEnter.append("text")
	  .attr("x", function(d) { return d.children || d._children ? -13 : 13; })
	  .attr("dy", ".35em")
	  .attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
	  .text(function(d) { return d.name; })
	  .style("fill-opacity", 1e-6);

  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
	  .duration(duration)
	  .attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });

  nodeUpdate.select("circle")
	  .attr("r", 10)
	  .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

  nodeUpdate.select("text")
	  .style("fill-opacity", 1);

  // Transition exiting nodes to the parent's new position.
  var nodeExit = node.exit().transition()
	  .duration(duration)
	  .attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
	  .remove();

  nodeExit.select("circle")
	  .attr("r", 1e-6);

  nodeExit.select("text")
	  .style("fill-opacity", 1e-6);

  // Update the links…
  var link = svg.selectAll("path.link")
	  .data(links, function(d) { return d.target.id; });

  // Enter any new links at the parent's previous position.
  link.enter().insert("path", "g")
	  .attr("class", "link")
	  .attr("d", function(d) {
		var o = {x: source.x0, y: source.y0};
		return diagonal({source: o, target: o});
	  });

  // Transition links to their new position.
  link.transition()
	  .duration(duration)
	  .attr("d", diagonal);

  // Transition exiting nodes to the parent's new position.
  link.exit().transition()
	  .duration(duration)
	  .attr("d", function(d) {
		var o = {x: source.x, y: source.y};
		return diagonal({source: o, target: o});
	  })
	  .remove();

  // Stash the old positions for transition.
  nodes.forEach(function(d) {
	d.x0 = d.x;
	d.y0 = d.y;
  });
}

// Toggle children on click.
function click(d) {
  if (d.children) {
	d._children = d.children;
	d.children = null;
  } else {
	d.children = d._children;
	d._children = null;
  }
  update(d);
}

</script>
	
  </body>
</html>
＆＃13;
＆＃13;
＆＃13;

答案 1 :(得分：0)

不仅要交换节点（x，y），还要连接节点的链路，即

var diagonal = d3.svg.diagonal()
            .projection(function(d) {return [d.y,d.x];});

答案 2 :(得分：0)

看看我做的这个例子

<!doctype html>
<html>
<head>
    <script src="http://d3js.org/d3.v3.min.js"></script>
</head>
<body>
<script>
    var data = {
        "name" : "A",
        "children" : [
        {
            "name" : "B",
            "children" : [
            {
                "name" : "F"
            },
            {
                "name" : "G"
            }
            ]
        },
        {
            "name" : "C",
            "children" : [
            {
                "name" : "H"
            },
            {
                "name" : "I"
            },
            {
                "name" : "J"
            }
            ]
        },
        {
            "name" : "D",
            "children" : [
            {
                "name" : "K"
            },
            {
                "name" : "L"
            }
            ]
        },
        {
            "name" : "E"
        }
        ]
    };

    var canvas = d3.select("body")
        .append("svg")
        .attr("width",600)
        .attr("height",500)
        .append("g")
            .attr("transform","translate(50,50)");

    var cluster = d3.layout.cluster()
        .size([400,400]);

    var nodes = cluster.nodes(data);
    var links = cluster.links(nodes);

    var node = canvas.selectAll(".node")
        .data(nodes)
        .enter()
        .append("g")
            .attr("class","node")
            .attr("transform",function(d) {return "translate(" + d.y + "," + d.x + ")"});

    node.append("circle")
        .attr("r",5)
        .attr("fill","silver");

    node.append("text")
        .text(function(d) {return d.name;});

    var diagonal = d3.svg.diagonal()
        .projection(function(d) {return [d.y,d.x];});

    canvas.selectAll(".link")
        .data(links)
        .enter()
        .append("path")
            .attr("class","link")
            .attr("fill","none")
            .attr("stroke","#ADADAD")
            .attr("d",diagonal); 

</script>

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