我通过实时两个相机流提取2个blob的x位置。我可以得到第一个x位置没问题,因为它是作为元组给出的(ex = ... object at(455,69))。问题是我需要第二个blob左下角的x位置,但它返回一个numpy数组,'blob.x'不起作用。如何获得numpy数组的x位置?非常感谢任何帮助/指导。
我收到以下错误: ValueError:具有多个元素的数组的真值是不明确的。使用a.any()或a.all()
from SimpleCV import *
def getscoreforrgb(rgb):
return rgbmap[rgb]
mog1 = MOGSegmentation(history = 200, nMixtures = 5, backgroundRatio = 0.9, noiseSigma = 16, learningRate = 0.9)
mog0 = MOGSegmentation(history = 200, nMixtures = 5, backgroundRatio = 0.9, noiseSigma = 16, learningRate = 0.9)
cam1 = SimpleCV.Camera(1, {'width': 640, 'height': 480 })
cam0 = SimpleCV.Camera(0, {'width': 640, 'height': 480 })
pixcol = Image('/home/pi/Darts/score/scoreboardpy.png')
while True:
frame1 = cam1.getImage()
frame0 = cam0.getImage().flipHorizontal()
mog1.addImage(frame1)
mog0.addImage(frame0)
segmentedImage1 = mog1.getSegmentedImage()
segmentedImage0 = mog0.getSegmentedImage()
#### second blob below, does not print x position
blobs0 = segmentedImage0.findBlobs()
if blobs0 is not None:
blobs0.sortArea()
blobs0[-1].draw(Color.BLUE, width=4)
first_blob = blobs0[-1]
bottomLeftCorner = second_blob.bottomLeftCorners()
print bottomLeftCorner
if bottomLeftCorner:
print bottomLeftCorner.x,
y = int(bottomLeftCorner.x)
print y * 2, 'Y'
y2 = y * 2
#### First blob below, code prints x position
blobs1 = segmentedImage1.findBlobs()
if blobs1 is not None:
blobs1.sortArea()
blobs1[-1].draw(Color.RED, width=4)
second_blob = blobs1[-1]
if second_blob:
print second_blob.x,
x = int(second_blob.x)
print x * 2, 'X'
x2 = x * 2
colrgb = pixcol[x2, y2]
print colrgb
答案 0 :(得分:1)
y2
,则不会定义 blobs0 is None
,在这种情况下,您可能不想做任何事情。
我建议您将所有内容放在一个if
块中:
blobs0 = segmentedImage0.findBlobs()
blobs1 = segmentedImage1.findBlobs()
if blobs0 is not None and blobs1 is not None:
# all your code here
您似乎在第一个块中使用second_blob
而不是first_blob
。你应该理解你的代码正在做什么,而不是盲目地使用一些希望它可以工作的旧代码块。