是否可以基于hierarchy / cte创建视图?
我已经看到了一个关于如何根据链接recursive query生成结果集的示例 我附上了ddl和声明。
谢谢你,
埃尔默
CREATE TABLE [dbo].[XHR_PERSON](
[PERSON_ID] [bigint] NOT NULL,
[LAST_NAME] [varchar](100) NOT NULL,
[FIRST_NAME] [varchar](100)
,EFFECTIVE_START_DATE Date
,EFFECTIVE_END_DATE Date)
CREATE TABLE [dbo].[XHR_EMPLOYMENT](
[PERSON_ID] [bigint] NOT NULL,
[EMPLOYEE_NUMBER] [varchar](100) NULL,
[SUPERVISOR_ID] [bigint] NULL
,EFFECTIVE_START_DATE Date
,EFFECTIVE_END_DATE Date)
insert into XHR_PERSON
select 1, 'SMY', null, '1990-01-01','9999-12-31' UNION ALL
select 2, 'JSB',null, '1990-01-01','9999-12-31' union all
select 3, 'LFG',null, '1990-01-01','9999-12-31' union all
select 4, 'Elmer',null, '1990-01-01','9999-12-31' union all
select 5, 'Jon',null, '1990-01-01','9999-12-31' union all
select 6, 'Anne',null, '1990-01-01','9999-12-31' union all
select 7, 'Teddy',null, '1990-01-01','9999-12-31' union all
select 8, 'Alex',null , '1990-01-01','9999-12-31'union all
select 9, 'Jeff',null, '1990-01-01','9999-12-31'
update XHR_PERSON set first_name = 'A'
insert into XHR_EMPLOYMENT
select 1, '111',null, '1990-01-01','9999-12-31' UNION ALL
select 2, '222',1, '1990-01-01','9999-12-31' union all
select 3, '333',1, '1990-01-01','9999-12-31' union all
select 4, '444',2, '1990-01-01','9999-12-31' union all
select 5, '555',2, '1990-01-01','9999-12-31' union all
select 6, '666',4, '1990-01-01','9999-12-31' union all
select 7, '777',3, '1990-01-01','9999-12-31' union all
select 8, '888',3, '1990-01-01','9999-12-31' union all
select 9, '999',8, '1990-01-01','9999-12-31'
CREATE VIEW dbo.HR_DIRECTREPORTSV as
WITH xxDirectReports (Supervisor_id, Person_id, Employee_number, Employee_name, Supervisor_Empno, Supervisor_Name, Level1)
AS
(
SELECT hre.Supervisor_id
,hre.Person_id
,hre.Employee_number
,hrp.last_name+', '+hrp.first_name Employee_Name
,hrpx.employee_number Supervisor_Empno
,hrpx.fullname Supervisor_Name
,0 AS Level1
FROM dbo.xhr_employment AS hre left join (select hrp1.person_id,hre1.employee_number ,(hrp1.last_name+', '+hrp1.first_name) as fullname
from dbo.xHR_PERSON hrp1
,dbo.xhr_employment hre1
where hrp1.person_id = hre1.person_id
AND getdate() between hrp1.effective_start_date
and hrp1.effective_end_date
) hrpx on hre.supervisor_id = hrpx.person_id
,dbo.xHR_PERSON AS hrp
WHERE hre.person_id = hrp.person_id
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date
--AND hrpx.person_id = 1
UNION ALL
SELECT hre.Supervisor_id
,hre.Person_id
,hre.Employee_number
,hrp.last_name+', '+hrp.first_name Employee_Name
,hrpx.employee_number Supervisor_Empno
,hrpx.fullname Supervisor_Name
,Level1+1
FROM dbo.xhr_employment AS hre inner join (select hrp1.person_id
,hre1.employee_number
,(hrp1.last_name+', '+hrp1.first_name) as fullname
from dbo.xHR_PERSON hrp1
,dbo.xhr_employment hre1
where hrp1.person_id = hre1.person_id
AND getdate() between hrp1.effective_start_date
and hrp1.effective_end_date
) hrpx on hre.supervisor_id = hrpx.person_id
INNER JOIN xxDirectReports AS xx ON hre.Supervisor_id = xx.Person_id
,dbo.xHR_PERSON AS hrp
WHERE hre.person_id = hrp.person_id
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date)
答案 0 :(得分:3)
在指定WITH
后(超出右括号),您需要从CTE中选择所有值:
select * from xxDirectReports
这是构成视图的实际选择查询。
这是完整的工作示例,选择视图的最终输出,以及一些额外的GO
语句,以允许语句在SQL Server Management Studio中的单次执行中运行:
if not OBJECT_ID('XHR_PERSON', 'Table') is null drop table XHR_PERSON
if not OBJECT_ID('XHR_EMPLOYMENT', 'Table') is null drop table XHR_EMPLOYMENT
if not OBJECT_ID('HR_DIRECTREPORTSV', 'View') is null drop view HR_DIRECTREPORTSV
CREATE TABLE [dbo].[XHR_PERSON](
[PERSON_ID] [bigint] NOT NULL,
[LAST_NAME] [varchar](100) NOT NULL,
[FIRST_NAME] [varchar](100)
,EFFECTIVE_START_DATE Date
,EFFECTIVE_END_DATE Date)
CREATE TABLE [dbo].[XHR_EMPLOYMENT](
[PERSON_ID] [bigint] NOT NULL,
[EMPLOYEE_NUMBER] [varchar](100) NULL,
[SUPERVISOR_ID] [bigint] NULL
,EFFECTIVE_START_DATE Date
,EFFECTIVE_END_DATE Date)
insert into XHR_PERSON
select 1, 'SMY', null, '1990-01-01','9999-12-31' UNION ALL
select 2, 'JSB',null, '1990-01-01','9999-12-31' union all
select 3, 'LFG',null, '1990-01-01','9999-12-31' union all
select 4, 'Elmer',null, '1990-01-01','9999-12-31' union all
select 5, 'Jon',null, '1990-01-01','9999-12-31' union all
select 6, 'Anne',null, '1990-01-01','9999-12-31' union all
select 7, 'Teddy',null, '1990-01-01','9999-12-31' union all
select 8, 'Alex',null , '1990-01-01','9999-12-31'union all
select 9, 'Jeff',null, '1990-01-01','9999-12-31'
update XHR_PERSON set first_name = 'A'
insert into XHR_EMPLOYMENT
select 1, '111',null, '1990-01-01','9999-12-31' UNION ALL
select 2, '222',1, '1990-01-01','9999-12-31' union all
select 3, '333',1, '1990-01-01','9999-12-31' union all
select 4, '444',2, '1990-01-01','9999-12-31' union all
select 5, '555',2, '1990-01-01','9999-12-31' union all
select 6, '666',4, '1990-01-01','9999-12-31' union all
select 7, '777',3, '1990-01-01','9999-12-31' union all
select 8, '888',3, '1990-01-01','9999-12-31' union all
select 9, '999',8, '1990-01-01','9999-12-31';
GO
CREATE VIEW dbo.HR_DIRECTREPORTSV as
WITH xxDirectReports (Supervisor_id, Person_id, Employee_number, Employee_name, Supervisor_Empno, Supervisor_Name, Level1)
AS
(
SELECT hre.Supervisor_id
,hre.Person_id
,hre.Employee_number
,hrp.last_name+', '+hrp.first_name Employee_Name
,hrpx.employee_number Supervisor_Empno
,hrpx.fullname Supervisor_Name
,0 AS Level1
FROM dbo.xhr_employment AS hre left join (select hrp1.person_id,hre1.employee_number ,(hrp1.last_name+', '+hrp1.first_name) as fullname
from dbo.xHR_PERSON hrp1
,dbo.xhr_employment hre1
where hrp1.person_id = hre1.person_id
AND getdate() between hrp1.effective_start_date
and hrp1.effective_end_date
) hrpx on hre.supervisor_id = hrpx.person_id
,dbo.xHR_PERSON AS hrp
WHERE hre.person_id = hrp.person_id
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date
--AND hrpx.person_id = 1
UNION ALL
SELECT hre.Supervisor_id
,hre.Person_id
,hre.Employee_number
,hrp.last_name+', '+hrp.first_name Employee_Name
,hrpx.employee_number Supervisor_Empno
,hrpx.fullname Supervisor_Name
,Level1+1
FROM dbo.xhr_employment AS hre inner join (select hrp1.person_id
,hre1.employee_number
,(hrp1.last_name+', '+hrp1.first_name) as fullname
from dbo.xHR_PERSON hrp1
,dbo.xhr_employment hre1
where hrp1.person_id = hre1.person_id
AND getdate() between hrp1.effective_start_date
and hrp1.effective_end_date
) hrpx on hre.supervisor_id = hrpx.person_id
INNER JOIN xxDirectReports AS xx ON hre.Supervisor_id = xx.Person_id
,dbo.xHR_PERSON AS hrp
WHERE hre.person_id = hrp.person_id
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date
AND GETDATE() between hrp.effective_start_date and hrp.effective_end_date)
select * from xxDirectReports;
GO
select * from HR_DIRECTREPORTSV;
<强>更新强>
此外,是否可以获取 以...开头的记录 样本数据,LFG而不是SMY?
是的!虽然方法各不相同。 我建议在CTE的锚定语句中使用变量,而不是拥有视图,将其创建为表值函数。但是,一旦采用分层数据,有许多不同的方法可以选择分层数据......其中一种方法是分层路径。
要添加此行为,请在Path
子句中添加WITH
列名称,并首先在锚语句中添加以下内容:
convert(nvarchar(256), RTRIM(convert(nvarchar(12), hre.PERSON_ID))) Path
其次,在递归声明中:
convert(nvarchar(256), rtrim(Path) + '.' + RTRIM(convert(nvarchar(12), hre.PERSON_ID))) Path
然后,要选择层次结构根(LFG)和所有下属,只需将从视图中选择的查询修改为:
select * from HR_DIRECTREPORTSV
where Path = '3' or Path like '3.%'
结果如下:
Path Supervisor_id Person_id Employee_number Employee_name Supervisor_Empno Supervisor_Name Level1
3 1 3 333 LFG, A 111 SMY, A 0
3.7 3 7 777 Teddy, A 333 LFG, A 1
3.8 3 8 888 Alex, A 333 LFG, A 1
3.8.9 8 9 999 Jeff, A 888 Alex, A 2
答案 1 :(得分:2)
是的,你可以 - 像
CREATE VIEW [mySchema].vwItem
AS
WITH cteItem
AS
(
SELECT
item_id AS 'ItemID',
item_level AS 'ItemLevel',
item_number_type AS 'ItemNumberType',
CASE item_level
WHEN 1 THEN item_id
WHEN 2 THEN item_parent_id
WHEN 3 THEN item_grandparent_id
ELSE item_id
END AS 'ItemParent',
FROM
[mySchema].[ITEM]
)
SELECT
child.*,
parent.item_id AS 'ParentId',
parent.desc AS 'ParentDescription'
FROM
cteItem child
LEFT OUTER JOIN [mySchema].[ITEM] parent ON
child.ItemParent = parent.item_id