Question

我正在尝试在我的桌子上创建一个CTE来吸引员工的层次结构。

我有一个起点是“导演”，我希望找到向每个人报告的每个人。

这是我到目前为止所做的：

;WITH EmpTable_CTE (FirstName, LastName, QID, Email) AS
    (
        SELECT      FirstName,
                    LastName,
                    QID,
                    Email
        FROM        EmployeeTable E
        WHERE       QID = '12345'

        UNION ALL

        SELECT      E.FirstName,
                    E.LastName,
                    E.QID,
                    E.Email
        FROM        EmployeeTable E
        INNER JOIN  EmpTable_CTE AS E2 ON E.MgrQID = E2.QID
    )
    SELECT * FROM EmpTable_CTE

这似乎可以为我提供一份员工清单，但它没有“层次结构”。

如何使用FOR XML创建我正在寻找的层次结构？

<Director>Bob Smith</Director>
    <Direct>Jim Smith</Direct>
        <Direct>Employee 1</direct>
        <Direct>Employee 2</direct>
        <Direct>Employee 3</direct>
    <Direct>Bob Jones</Direct>
        <Direct>Employee 1</direct>
        <Direct>Employee 2</direct>
        <Direct>Employee 3</direct>
            <Direct>Employee A</direct>

我确定这只是将FOR XML行置于某个地方，但无法弄明白。

更新：这是一个示例数据的SQL小提琴：

http://sqlfiddle.com/#!6/a48f6/1

这就是我期望数据来自小提琴的方式：

<Director>Jim Jones</Director>
    <Direct>Bob Jones</Direct>
        <Direct>Jake Jones</Direct>
        <Direct>Smith Jones</Direct>
            <Direct>Carl Jones</Direct>
                <Direct>Bobby Jones</Direct>
    <Direct>Danny Jones</Direct>
        <Direct>Billy Jones</Direct>

Answer 1

部分困难在于您提供的XML结构 - 如果您将其传递给解析器，它将全部是平面的，并且运行我的流程结果，而不会将First和Last名称填充到属性中以混合内容出现（带有同一级别节点的文本）。

所以，我去搜索并找到了this little gem here on SE。根据你的需要调整它，并将几个字段作为表中的属性，我提出了这个：

CREATE FUNCTION dbo.EmpHierarchyNode(@QID int)
RETURNS XML
WITH RETURNS NULL ON NULL INPUT 
BEGIN RETURN 
  (SELECT QID AS "@ID", Email AS "@Email",
    FirstName + ' ' + LastName AS "@Name",
      CASE WHEN MgrQID = @QID
      THEN dbo.EmpHierarchyNode(QID)
      END
   FROM dbo.EmployeeTable
   WHERE MgrQID = @QID
   FOR XML PATH('Direct'), TYPE)
END

SELECT  QID AS "@ID", Email AS "@Email",
    FirstName + ' ' + LastName AS "@Name",
    dbo.EmpHierarchyNode(QID)
FROM dbo.EmployeeTable
WHERE MgrQID IS NULL
FOR XML PATH('Director'), TYPE

本质上，它遍历层次结构，以递归方式调用自身。如果您的输出是针对XML的，那么CTE是不够的。使用这个，以及我可以收集的样本数据，我得到了这个结果：

<Director ID="1" Email="bsmith@someCompany.com" Name="Bob Smith">
  <Direct ID="2" Email="jsmith@someCompany.com" Name="Jim Smith">
    <Direct ID="4" Email="e1@someCompany.com" Name="Employee 1" />
    <Direct ID="5" Email="e2@someCompany.com" Name="Employee 2" />
    <Direct ID="7" Email="e4@someCompany.com" Name="Employee 4" />
  </Direct>
  <Direct ID="3" Email="bjones@someCompany.com" Name="Bob Jones">
    <Direct ID="6" Email="e3@someCompany.com" Name="Employee 3" />
    <Direct ID="8" Email="e5@someCompany.com" Name="Employee 5" />
    <Direct ID="9" Email="e6@someCompany.com" Name="Employee 6" />
  </Direct>
</Director>

希望这有帮助。

编辑：最后一分钟SQLFiddle Example。

Answer 2

看看它是否符合您的要求：

;WITH EmpTable_CTE (FirstName, LastName, QID, Email) AS
    (
        SELECT      FirstName,
                    LastName,
                    QID,
                    Email
        FROM        EmployeeTable E
        WHERE       QID = 1
        UNION ALL
        SELECT      E.FirstName,
                    E.LastName,
                    E.QID,
                    E.Email
        FROM        EmployeeTable E
        INNER JOIN  EmpTable_CTE AS E2
        ON          E.MgrQID = E2.QID
    )

    SELECT LastName + ', ' + FirstName FROM EmpTable_CTE FOR XML PATH('Direct'), ROOT('Director'), TYPE

TSQL CTE层次结构

2 个答案: