我的伺服和超声波有问题,无法顺利运行。我的代码现在工作如下:伺服将每10秒移动一次,超声波总是检测范围并在LED上显示结果。 我正在寻找谷歌的参考资料,我发现延迟导致伺服和超声波无法一起运行。为了使用millis()需要多任务处理。但我仍然无法使用函数millis()。 如何用millis()更改代码中的延迟?
感谢您的帮助!
#include <Servo.h>
#define trigPin 13
#define echoPin 12
#define ledM 10
#define ledK 9
#define ledH 8
Servo ikiservo; //servo
int pos = 0; //set positon servo
int pinSpeaker = 4; //buzzer
void setup() {
Serial.begin (9600); //SERIAL
ikiservo.attach(3); //servo
pinMode(pinSpeaker, OUTPUT);
pinMode(trigPin, OUTPUT); //ultrasonic
pinMode(echoPin, INPUT); //ultrasonic
pinMode(ledM, OUTPUT);
pinMode(ledK, OUTPUT);
pinMode(ledH, OUTPUT);
}
void loop() {
//-------------SERVO----------
for(pos = 0; pos < 90; pos += 1) // goes from 0 degrees to 90 degrees
{ // in steps of 1 degree
ikiservo.write(pos);
delay(10000); // waits 10s for the servo to reach the position
}
//---------ULTRASONIC-----------
long duration, distance;
digitalWrite(trigPin, LOW);
delayMicroseconds(2);
digitalWrite(trigPin, HIGH);
delayMicroseconds(10);
digitalWrite(trigPin, LOW);
duration = pulseIn(echoPin, HIGH);
distance = (duration/2) / 29.1;
Serial.print(distance);
Serial.println(" cm");
delay (400);
if (distance > 4 && distance <7) { // turn on ledM when distance 4<distance<7
digitalWrite(ledM,HIGH);
digitalWrite(ledK,LOW);
digitalWrite(ledH,LOW);
playTone(300, 160); //buzzer ON
delay(1000);
//buzzer
} else if(distance > 2 && distance <4) {// turn on ledK when 7<distance<4
digitalWrite(ledM,LOW);
digitalWrite(ledK,HIGH);
digitalWrite(ledH,LOW);
playTone(0, 0);
delay(1000);
} else if(distance <2) {//turn on ledH when distance<2
digitalWrite(ledM,LOW);
digitalWrite(ledK,LOW);
digitalWrite(ledH,HIGH);
playTone(0, 0);
delay(1000);
} else{ //turn off all
digitalWrite(ledM,LOW);
digitalWrite(ledK,LOW);
digitalWrite(ledH,LOW);
playTone(0, 0);
delay(1000);
}
}
void playTone(long duration, int freq) { //funtion for add tone on buzzer
duration *= 1000;
int period = (1.0 / freq) * 1000000;
long elapsed_time = 0;
while (elapsed_time < duration) {
digitalWrite(pinSpeaker,HIGH);
delayMicroseconds(period / 2);
digitalWrite(pinSpeaker, LOW);
delayMicroseconds(period / 2);
elapsed_time += (period);
}
}
答案 0 :(得分:0)
你不是等待10秒钟,而是15分钟。可能是你的代码中唯一的问题。
请写下这个
for(pos = 0; pos < 90; pos += 1) // goes from 0 degrees to 90 degrees
{ // in steps of 1 degree
ikiservo.write(pos);
delay(100); // waits 0.1s for the servo to reach the position
// so total time will be 9 seconds
}
另一方面,如果你想在10秒内跨越90°区域,那么回去吧,代码是
void loop() {
//-------------SERVO----------
for(pos = 0; pos < 90; pos += 1) // goes from 0 degrees to 90 degrees
{ // in steps of 1 degree
ikiservo.write(pos);
//---------ULTRASONIC-----------
long duration, distance;
digitalWrite(trigPin, LOW);
delayMicroseconds(2);
digitalWrite(trigPin, HIGH);
delayMicroseconds(10);
digitalWrite(trigPin, LOW);
duration = pulseIn(echoPin, HIGH);
distance = (duration/2) / 29.1;
Serial.print(distance);
Serial.println(" cm");
if (distance > 4 && distance <7) { // turn on ledM when distance 4<distance<7
digitalWrite(ledM,HIGH);
digitalWrite(ledK,LOW);
digitalWrite(ledH,LOW);
} else if(distance > 2 && distance <4) {// turn on ledK when 7<distance<4
digitalWrite(ledM,LOW);
digitalWrite(ledK,HIGH);
digitalWrite(ledH,LOW);
} else if(distance <2) {//turn on ledH when distance<2
digitalWrite(ledM,LOW);
digitalWrite(ledK,LOW);
digitalWrite(ledH,HIGH);
} else{ //turn off all
digitalWrite(ledM,LOW);
digitalWrite(ledK,LOW);
digitalWrite(ledH,LOW);
}
delay(100); // waits 0.1s for the servo to reach the position
}
}
我不得不删除音调,因为你使用它的方式不允许其他“进程”同时工作。看看它是否是您想要的方法;如果是报告,我们可以看到如何使用蜂鸣器实现它