Question

我想检查一个字符串是否包含另一个字符串的字符（返回true或false），但它必须是“正确”的顺序，但不一定是连续的。

示例：

String firstWord = "arm";
String secondWord = "arandomword"; //TRUE - ARandoMword

String thirdWord = "road"; //FALSE - ARanDOmword

单词“arandomword”包含单词“road”的字母，但不可能写出来，因为它们的顺序不正确。

任何人，拜托？

Answer 1

使用正则表达式。在linqpad中传递测试的简单方法：

void Main()
{
    String firstWord = "arm";
    String secondWord = "arandomword"; //TRUE - ARandoMword

    String thirdWord = "road";

    Regex.IsMatch(secondWord,makeRegex(firstWord.ToCharArray())).Dump();
}

// Define other methods and classes here
String makeRegex(char[] chars)
{
    StringBuilder sb = new StringBuilder();
    foreach (var element in chars.Select(c => Regex.Escape(c.ToString()))
        .Select(c => c + ".*"))
    {
        sb.Append(element);
    }
    return sb.ToString();
}

Answer 2

你可以像这样定义一个扩展方法：

public static class StringExtensions
{
    public static bool ContainsWord(this string word, string otherword)
    {
        int currentIndex = 0;

        foreach(var character in otherword)
        {
            if ((currentIndex = word.IndexOf(character, currentIndex)) == -1)
                return false;
        }

        return true;
    }
}

并将其称为表达：

String firstWord = "arm";
String secondWord = "arandomword"; //TRUE - ARandoMword
String thirdWord = "road"; //FALSE - ARanDOmword

var ret = secondWord.ContainsWord(firstWord); // true
var ret2 = thirdWord.ContainsWord(firstWord); // false

Answer 3

这样的东西？

bool HasLettersInOrder(string firstWord, string secondWord)
{
    int lastPos = -1;
    foreach (char c in firstWord)
    {
        lastPos++;
        while (lastPos < secondWord.Length && secondWord[lastPos] != c)
            lastPos++;
        if (lastPos == secondWord.Length)
            return false;
    }
    return true;
}

Answer 4

我现在无法检查，但有些事情是这样的：

int i = 0, j = 0;

while(i < first.Length && j < second.Length)
{
   while(first[i] != second[j] && j < second.Length) j++;
   i++;
   j++
}

bool b = i == first.Length;

Answer 5

感谢所有回复。我尝试过并试过，我按照自己的方式做到了。确切地说，它不是最短的方式，但至少它起作用了：

    public static Boolean checkWords(String smallerWord, String biggerWord)
    {
        int position = 0;
        bool gotFirst = false;
        bool gotAnother = false;
        int positionBigger = 0;
        String word = "";

        for(int positionSmaller = 0; positionSmaller < smallerWord.Length; positionSmaller++)
        {
            if(!gotFirst)
            {
                if(biggerWord.Contains(smallerWord[positionSmaller].ToString()))
                {
                    position = biggerWord.IndexOf(smallerWord[positionSmaller].ToString());
                    gotFirst = true;
                    word = smallerWord[positionSmaller].ToString();
                }
            }
            else
            {
                gotAnother = false;
                positionBigger = position + 1;

                while(!gotAnother)
                {
                    if(positionBigger < biggerWord.Length)
                    {
                        if(biggerWord[positionBigger].ToString().Equals(smallerWord[positionSmaller].ToString()))
                        {
                            position = positionBigger;
                            gotAnother = true;
                            word += smallerWord[positionSmaller].ToString();
                        }
                        else
                        {
                            positionBigger++;
                        }
                    }
                    else
                    {
                        gotAnother = true;
                    }
                }
            }
        }

        if(smallerWord.Equals(word))
        {
            return true;
        }
        else
        {
            return false;
        }
    }

C＃ - 检查字符串是否包含相同顺序的另一个字符串的字符

5 个答案: