我有以下HTML结构(无尽的)......
<div class="wrapper">
<div class="content">
<div class="score">1</div>
<div class="score">2.5</div>
<div class="score">1.5</div>
<div class="score">1.5</div>
<div class="score">2</div>
</div>
</div>
...我希望,该脚本为每个包装器添加1到5的分数。每个包装器的结果应显示在一个名为&#34; result&#34;的新div中。这个div也应该由脚本创建。
看起来像这样::
<div class="wrapper">
<div class="content">
<div class="score">1</div>
<div class="score">2.5</div>
<div class="score">1.5</div>
<div class="score">1.5</div>
<div class="score">2</div>
<div class="result">8.5</div> <-- created by script
</div>
</div>
<div class="wrapper">
<div class="content">
<div class="score">2.5</div>
<div class="score">3.5</div>
<div class="score">4</div>
<div class="score">1.5</div>
<div class="score">1</div>
<div class="result">12.5</div> <-- created by script
</div>
</div>
<div class="wrapper">
<div class="content">
<div class="score">4</div>
<div class="score">1.5</div>
<div class="score">2.5</div>
<div class="score">2</div>
<div class="score">1.5</div>
<div class="result">11.5</div> <-- created by script
</div>
</div>
我的问题:
a)如果类名总是相同的(包装器,内容,分数),如何为每个包装器添加正确的分数?
b)如何自动为每个包装器创建一个包含结果的div?
任何人都可以帮助我吗?
答案 0 :(得分:2)
迭代每个.content
元素,然后追加.score
元素的总和。
您可以通过嵌套.each()
loops:
$('.wrapper .content').each(function () {
var sum = 0;
$(this).find('.score').each(function () {
sum += Number($(this).text(), 10);
});
$(this).append('<div class="result">' + sum + '</div>');
});
$('.wrapper .content').each(function () {
var sum = 0;
$(this).find('.score').each(function () {
sum += Number($(this).text(), 10);
});
$(this).append('<div class="result">' + sum + '</div>');
});
&#13;
.result {
color: #f00;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrapper">
<div class="content">
<div class="score">1</div>
<div class="score">2.5</div>
<div class="score">1.5</div>
<div class="score">1.5</div>
<div class="score">2</div>
</div>
</div>
<div class="wrapper">
<div class="content">
<div class="score">2.5</div>
<div class="score">3.5</div>
<div class="score">4</div>
<div class="score">1.5</div>
<div class="score">1</div>
</div>
</div>
<div class="wrapper">
<div class="content">
<div class="score">4</div>
<div class="score">1.5</div>
<div class="score">2.5</div>
<div class="score">2</div>
<div class="score">1.5</div>
</div>
</div>
&#13;
var content = document.querySelectorAll('.wrapper .content');
Array.prototype.forEach.call(content, function (el) {
var score = el.querySelectorAll('.score'),
resultElement = document.createElement('div'),
sum = 0;
Array.prototype.forEach.call(score, function (el) {
sum += Number(el.textContent, 10);
});
resultElement.className += 'result';
resultElement.textContent = sum;
el.appendChild(resultElement);
});
答案 1 :(得分:1)
$(document).ready(function(){
$('.content').each(function(){
var total = 0;
$(this).find('> .score').each(function(){
total += parseFloat($(this).text());
});
$(this).append('<div class="result">' + total + '</div>');
});
});
答案 2 :(得分:0)
您可以使用jQuery的DOM each
:
var finalVal = 0;
$(function () {
$(".content").each(function () {
finalVal = 0;
$(this).find(".score").each(function () {
finalVal += Number($(this).text());
});
$(this).append('<div class="result">' + finalVal + '</div>');
finalVal = 0;
});
});
.result {background: #99f;}
<script src="https://code.jquery.com/jquery-1.9.1.js"></script>
<div class="wrapper">
<div class="content">
<div class="score">1</div>
<div class="score">2.5</div>
<div class="score">1.5</div>
<div class="score">1.5</div>
<div class="score">2</div>
</div>
</div>
<div class="wrapper">
<div class="content">
<div class="score">2.5</div>
<div class="score">3.5</div>
<div class="score">4</div>
<div class="score">1.5</div>
<div class="score">1</div>
</div>
</div>
<div class="wrapper">
<div class="content">
<div class="score">4</div>
<div class="score">1.5</div>
<div class="score">2.5</div>
<div class="score">2</div>
<div class="score">1.5</div>
</div>
</div>