生成随机LatLng给定设备位置和半径

时间:2015-11-28 21:38:34

标签: android google-maps android-maps-v2

我正试图在给定位置附近的地图上生成随机点。我有一个circle形状,它围绕半径为100的用户位置,我想在这个圆圈区域内生成随机LatLng坐标。到目前为止,我已经提出了以下功能,但点标记仍然出现在圆圈范围之外。

    double lat = location.getLatitude();
    double lon = location.getLongitude();

    for (int i = 0; i < markers.size(); i++) {
        Marker mrk = markers.get(i);

            Random random = new Random();


            double radiusInDegrees =mCircle.getRadius();

            double u = random.nextDouble();
            double v = random.nextDouble();
            double w = radiusInDegrees * Math.sqrt(u);
            double t = 2 * Math.PI * v;
            double x = w * Math.cos(t);
            double y = w * Math.sin(t);

            // Adjust the x-coordinate for the shrinking of the east-west distances
            double new_x = x / Math.cos(lat);

            double newLongitude = new_x + lon;
            double newLatitude = y + lat;


            mrk.setPosition(new LatLng(newLatitude,newLongitude));

    }

2 个答案:

答案 0 :(得分:8)

借助于此 php-jwt

我能够创建一个在一定半径范围内生成随机LatLng点的函数,其中半径以米为单位。

public LatLng getRandomLocation(LatLng point, int radius) {

        List<LatLng> randomPoints = new ArrayList<>();
        List<Float> randomDistances = new ArrayList<>();
        Location myLocation = new Location("");
        myLocation.setLatitude(point.latitude);
        myLocation.setLongitude(point.longitude);

        //This is to generate 10 random points
        for(int i = 0; i<10; i++) {
            double x0 = point.latitude;
            double y0 = point.longitude;

            Random random = new Random();

            // Convert radius from meters to degrees
            double radiusInDegrees = radius / 111000f;

            double u = random.nextDouble();
            double v = random.nextDouble();
            double w = radiusInDegrees * Math.sqrt(u);
            double t = 2 * Math.PI * v;
            double x = w * Math.cos(t);
            double y = w * Math.sin(t);

            // Adjust the x-coordinate for the shrinking of the east-west distances
            double new_x = x / Math.cos(y0);

            double foundLatitude = new_x + x0;
            double foundLongitude = y + y0;
            LatLng randomLatLng = new LatLng(foundLatitude, foundLongitude);
            randomPoints.add(randomLatLng);
            Location l1 = new Location("");
            l1.setLatitude(randomLatLng.latitude);
            l1.setLongitude(randomLatLng.longitude);
            randomDistances.add(l1.distanceTo(myLocation));
        }
        //Get nearest point to the centre
        int indexOfNearestPointToCentre = randomDistances.indexOf(Collections.min(randomDistances));
        return randomPoints.get(indexOfNearestPointToCentre);
    }

for循环的目的只是为了确保获得最近的随机点,因为我已经看到当我增加半径时,点已经离开了圆圈。你可以删除循环。

答案 1 :(得分:1)

这个答案应该有所帮助。它看起来就像你将半径从米转换为度数所做的那样。

  // Convert radius from meters to degrees
double radiusInDegrees = radius / 111000f;

See link here.