Question

我想在网上制作一个程序，通过用户的网络摄像头捕捉图像。

我正在使用getUserMedia Web API。这是我的代码，但它不起作用。如何更改它以捕获网络摄像头图像？

<div id="container">
    <video autoplay="true" id="videoElement">

    </video>
</div>
<script>

</script>

有JS：

var video = document.querySelector("#videoElement");

navigator.getUserMedia, elem = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia || navigator.msGetUserMedia || navigator.oGetUserMedia;

console.log(navigator.getUserMedia);

if (navigator.getUserMedia) {
    navigator.getUserMedia({video: true}, handleVideo, videoError);
}

function handleVideo(stream) {
    video.src = window.URL.createObjectURL(stream);
}

function videoError(e) {
    // do something
}

Answer 1

您可以使用此工作示例

 <!DOCTYPE html>
<html>
  <head>
  </head>
  <body onload="init();">
    <h1>Take a snapshot of the current video stream</h1>
   Click on the Start WebCam button.
     <p>
    <button onclick="startWebcam();">Start WebCam</button>
    <button onclick="stopWebcam();">Stop WebCam</button> 
       <button onclick="snapshot();">Take Snapshot</button> 
    </p>
    <video onclick="snapshot(this);" width=400 height=400 id="video" controls autoplay></video>
  <p>

        Screenshots : <p>
      <canvas  id="myCanvas" width="400" height="350"></canvas>  
  </body>
  <script>
      //--------------------
      // GET USER MEDIA CODE
      //--------------------
          navigator.getUserMedia = ( navigator.getUserMedia ||
                             navigator.webkitGetUserMedia ||
                             navigator.mozGetUserMedia ||
                             navigator.msGetUserMedia);

      var video;
      var webcamStream;

      function startWebcam() {
        if (navigator.getUserMedia) {
           navigator.getUserMedia (

              // constraints
              {
                 video: true,
                 audio: false
              },

              // successCallback
              function(localMediaStream) {
                  video = document.querySelector('video');
                 video.src = window.URL.createObjectURL(localMediaStream);
                 webcamStream = localMediaStream;
              },

              // errorCallback
              function(err) {
                 console.log("The following error occured: " + err);
              }
           );
        } else {
           console.log("getUserMedia not supported");
        }  
      }

      function stopWebcam() {
          webcamStream.stop();
      }
      //---------------------
      // TAKE A SNAPSHOT CODE
      //---------------------
      var canvas, ctx;

      function init() {
        // Get the canvas and obtain a context for
        // drawing in it
        canvas = document.getElementById("myCanvas");
        ctx = canvas.getContext('2d');
      }

      function snapshot() {
         // Draws current image from the video element into the canvas
        ctx.drawImage(video, 0,0, canvas.width, canvas.height);
      }

  </script>
</html>

Answer 2

getUserMedia api已经有了更新，现在公开了takePhoto和grabFrame。 grabFrame方法不那么令人兴奋，因为它完成了我们一直在做的事情，只是从流中返回下一个视频帧，但takePhoto中断流以使用摄像机＆＃34;最高可用的摄影摄像机分辨率＆＃34;捕获压缩的图像blob。更多详情：google devs

var stream, imageCapture; 

function getMediaStream()
{ 
    window.navigator.mediaDevices.getUserMedia({video: true})
    .then(function(mediaStream)
    { 
        stream = mediaStream; 
        let mediaStreamTrack = mediaStream.getVideoTracks()[0];
        imageCapture = new ImageCapture(mediaStreamTrack);
        console.log(imageCapture);
    })
    .catch(error);
}

function error(error)
{ 
    console.error('error:', error); 
}

function takePhoto(img)
{ 
    const img = img || document.querySelector('img');

    imageCapture.takePhoto()
    .then(blob => {
        let url = window.URL.createObjectURL(blob);
        img.src = url;
        window.URL.revokeObjectURL(url); 
    })
    .catch(error);
}; 

/* just call */ 
getMediaStream(); 

/* and when you want to capture an image */ 
takePhoto();

Answer 3

IE11不支持

getUserMedia ，请看这个链接：https://caniuse.com/#search=getuserMedia

因此，如果您仍然想使用getUserMedia的核心属性，那么您需要使用polyfill。看看这个polyfilllink：https://github.com/addyosmani/getUserMedia.js

如何使用getUserMedia通过用户的网络摄像头捕获图像？

3 个答案: