Question

刚开始学习Javascript

示例代码：

while() {

var int1 = parseInt(prompt("Enter 1st number"));

var int2 = parseInt(prompt("Enter 2nd number"));

var int3 = parseInt(prompt("Enter 3rd number"));

var final = (int1 * 2) + (int2 * 3) + (int3 * 4);

document.write(final);

}

此提示过程将循环播放3次。将显示3个var最终值。

如何将3 var final值存储到数组中，然后使用document.write显示最高var final值，最低var final值和average var final值。

Answer 1

循环并将其推入阵列是这样的;

var checkNumber = true, // Create a variable that eqausl true to start the while loop
    array = []; // creating the array

// Whenever checkNumber is true start!
while(checkNumber) {

var int1 = parseInt(prompt("Enter 1st number"));
array.push(int1) // Push int1 into the array
var int2 = parseInt(prompt("Enter 2nd number"));
array.push(int2) // Push int2 into the array
var int3 = parseInt(prompt("Enter 3rd number"));
array.push(int3) // Push int3 into the array
var final = (int1 * 2) + (int2 * 3) + (int3 * 4);
// Or like you have in final
// array.push(int1 * 2)
// Same for the rest!


// Checking with Math.max which number is greater
var largest = Math.max.apply(Math, array); 

alert(largest);

// Change the variable checkNumber to false to avoid a loop    
checkNumber = false;

}

Answer 2

实际上，您提供的代码会在while()循环的每个循环中请求3个输入。因此，如果您只需要3个数字，那么您将不需要while()循环。

我在下面编写了一组非常基本的代码，其中包含两个函数，可以找到数组中的最大值和最小值。

var totalSum = 0;
// initialize the array with 0s.
var inputNums = [0, 0, 0];

// Loop through the input number array and ask for a number each time.
for (var i = 0; i < inputNums.length; i++) {
    inputNums[i] = parseInt(prompt("Enter Number #" + (i + 1)));
    //Add the number to the total sum
    totalSum = totalSum + inputNums[i];
}

// Calculate results
var average = totalSum / inputNums.length;

document.write("Total Inputs: " + inputNums.length + "<br>");
document.write("Sum: " + totalSum + "<br>");
document.write("Average: " + average + "<br>");
document.write("Max: " + findMaxValue(inputNums) + "<br>");
document.write("Min: " + findMinValue(inputNums) + "<br>");

function findMaxValue(numArray) {
    // Initialize with first element in the array
    var result = numArray[0];

    for(var i = 1; i < numArray.length; i++) {
        // loops through each element in the array and stores it if it is the largest
        if(result < numArray[i]) {
            result = numArray[i];
        }
    }
    return result;
}

function findMinValue(numArray) {
    // Initialize with first element in the array
    var result = numArray[0];

    for(var i = 1; i < numArray.length; i++) {
        // loops through each element in the array and stores it if it is the smallest
        if(result > numArray[i]) {
            result = numArray[i];
        }
    }
    return result;
}

不幸的是，SO中的代码段系统不支持prompt()。

我在这里提出了一个问题：https://jsfiddle.net/hrt7b0jb/

Answer 3

在循环外声明一个数组变量。将其推送到格式为{iteration: i, value: ''}的数组，并使用item.value使用比较函数对循环后的数组进行排序。

Answer 4

您可以使用以下代码。

注意我修改了Array对象的原型，添加了两个新方法来获取min和max（从this answer中提取）。如果您需要增强此解决方案，则必须稍微更改一下代码。

config.asset_host = 'http://example.com'

链接到jsfiddle http://jsfiddle.net/gveuenhh/

Answer 5

var array = [];
while() {

var int1 = parseInt(prompt("Enter 1st number"));

var int2 = parseInt(prompt("Enter 2nd number"));

var int3 = parseInt(prompt("Enter 3rd number"));

var final = (int1 * 2) + (int2 * 3) + (int3 * 4);

array.push(final);

document.write(final);

}
var min = array[0], max = array[0];
for(var i = 0; i < array.length; i++){
     console.log(min, max)
if(min > array[i+1]){
console.log("if")
min = array[i+1]
}
else if(max < array[i+1]){
console.log("elseif")
max = array[i+1]
}
else{}
}

Javascript var提示进入Array，document.write（Max / Min / Average）;

5 个答案: