Question

我有两个数组

a = [1, 2, 3, 4, 5]

b = [2, 4, 6]

我想合并两个数组，然后删除与其他数组相同的值。结果应该是：

c = [1, 3, 5, 6]

我尝试减去两个数组，结果是[1,3,5]。我还想从第二个数组获取第一个数组中没有重复的值..

Answer 1

使用Array#uniq。

a = [1, 3, 5, 6]
b = [2, 3, 4, 5]

c = (a + b).uniq
=> [1, 3, 5, 6, 2, 4]

Answer 2

您可以执行以下操作！

# Merging
c = a + b
 => [1, 2, 3, 4, 5, 2, 4, 6]
# Removing the value of other array
# (a & b) is getting the common element from these two arrays
c - (a & b)
=> [1, 3, 5, 6]

尽管我独立提出了自己的想法，但Dmitri的评论也是一样的。

Answer 3

这个怎么样。

events = this.props.schedule.map(function(event) {
    return (
        <li className="animated" key={event.time}>
           <ScheduleEventItem event={event} />
        </li>
    );
});


return (
                <React.addons.CSSTransitionGroup className="animated" 
                    transitionName={{enter: "flipInX", leave: "flipOutX"}}
                    transitionEnterTimeout={1000} transitionLeaveTimeout={1}
                    >
                        {events}
                </React.addons.CSSTransitionGroup>
);

Documentation for | method
Documentation for & method

Answer 4

与Array#uniq相同：

a = [1, 3, 5, 6]
b = [2, 3, 4, 5]

a|b
=> [1, 3, 5, 6, 2, 4]

Source

Answer 5

Set.new([1,2,3]+[1,4,5])怎么样？返回[1,2,3,4,5]

Answer 6

Let's have two array

p = [1, 2, 5, 4, 8, 9]
q = [5, 6, 4, 8, 5, 3]

(p+q).uniq or (p.concat(q)).uniq

=> [1, 2, 5, 4, 8, 9, 6, 3]

Also p|q can do the job! Decide which one suits for you.

Ruby - 合并两个数组并删除具有重复的值

6 个答案: