我有两个数组,从结果中填充。
1)users_facebook& 2)users_twitter
Array
(
[users_facebook] => Array
(
[0] => Array
(
[id] => "180",
[email] => "",
[first_name] => "Djon",
[last_name] => "Katview"
),
[1] => Array
(
[id] => "182",
[email] => "",
[first_name] => "Awaaru",
[last_name] => "Bhejafry"
)
),
[users_twitter] => Array
(
[0] => Array
(
[id] => "180",
[email] => "",
[first_name] => "Djon",
[last_name] => "Katview"
),
[1] => Array
(
[id] => "181",
[email] => "",
[first_name] => "Kavritis",
[last_name] => "Abrfafda"
),
[2] => Array
(
[id] => "182",
[email] => "",
[first_name] => "Awaaru",
[last_name] => "Bhejafry"
)
),
)
我想在两个数组中选择具有相同“id”的元素,并将其附加到新数组,例如“users_final_array”
当它附加到新数组时,我想从两个数组中删除它。
p.s。:不匹配的元素必须保持原样。我差不多3小时就搞乱了它
添加了:
结果数组将如下:
Array
(
[users_facebook] => Array
(
),
[users_twitter] => Array
(
[0] => Array
(
[id] => "181",
[email] => "",
[first_name] => "Kavritis",
[last_name] => "Abrfafda"
)
),
[users_final_array] => Array
(
[0] => Array
(
[id] => "180",
[email] => "",
[first_name] => "Djon",
[last_name] => "Katview"
),
[1] => Array
(
[id] => "182",
[email] => "",
[first_name] => "Awaaru",
[last_name] => "Bhejafry"
)
),
)
答案 0 :(得分:2)
通过解码将其转换为json到数组。然后尝试将这两个数组合并为一个数组。合并后使用array_unique()函数删除重复内容如下
array_unique($merge_array);
答案 1 :(得分:0)
首先,这两个数组是JSON数组,所以将主题解码为php的一个:
$array = json_decode($response, true);
和thene,只需使用php“array_merge”并选择它们(facebook和twitter)
答案 2 :(得分:0)
<?php
$res = '{
"users_facebook": [
{
"id": "180",
"email": "",
"first_name": "Djon",
"last_name": "Matfew"
},
{
"id": "182",
"email": "",
"first_name": "Awaaru",
"last_name": "Bhejafry"
}
],
"users_twitter": [
{
"id": "180",
"email": "",
"first_name": "Djon",
"last_name": "Matfew"
},
{
"id": "181",
"email": "",
"first_name": "Kavritis",
"last_name": "Abrfafda"
},
{
"id": "182",
"email": "",
"first_name": "Awaaru",
"last_name": "Bhejafry"
}
]
}';
$res = json_decode($res, true);
print_r(array_intersect($res['users_facebook'],$res['users_twitter']));
?>
比array_diff看到原始回复中剩下的内容