Question

我正在对某些数据进行kNN分类。我有随机分割的数据，用于80/20比率的训练和测试集。我的数据如下：

[ [1.0, 1.52101, 13.64, 4.49, 1.1, 71.78, 0.06, 8.75, 0.0, 0.0, 1.0], 
  [2.0, 1.51761, 13.89, 3.6, 1.36, 72.73, 0.48, 7.83, 0.0, 0.0, 2.0],
  [3.0, 1.51618, 13.53, 3.55, 1.54, 72.99, 0.39, 7.78, 0.0, 0.0, 3.0],
  ...
]

矩阵的最后一列中的项目是类：1.0,2.0和3.0

在功能规范化之后，我的数据如下所示：

[[-0.5036443480260487, -0.03450760227559746, 0.06723230162846759, 0.23028986544844693, -0.025324623254270005, 0.010553065215338569, 0.0015136367098358505, -0.11291235596166802, -0.05819669234942126, -0.12069793876044387, 1.0], 
[-0.4989050339943617, -0.11566537753097901, 0.010637426608816412, 0.2175704556290625, 0.03073267976659575, 0.05764598316498372, -0.012976783512350588, -0.11815839520204152, -0.05819669234942126, -0.12069793876044387, 2.0],
...
]

我用于规范化的公式：

(X - avg(X)) / (max(X) - min(X))

我对 K = 1到25 （仅限奇数）中的每一个执行kNN分类 100 次。我记录了每个 K 的平均准确度。这是我的结果：

Average accuracy for K=1 after 100 tests with different data split: 98.91313003886198 %   
Average accuracy for K=3 after 100 tests with different data split: 98.11976006170633 %    
Average accuracy for K=5 after 100 tests with different data split: 97.71226079929019 %  
Average accuracy for K=7 after 100 tests with different data split: 97.47493145754373 %    
Average accuracy for K=9 after 100 tests with different data split: 97.16596220947888 %   
Average accuracy for K=11 after 100 tests with different data split: 96.81465365733266 %   
Average accuracy for K=13 after 100 tests with different data split: 95.78772655522567 %    
Average accuracy for K=15 after 100 tests with different data split: 95.23116406332706 %    
Average accuracy for K=17 after 100 tests with different data split: 94.52371789094929 %    
Average accuracy for K=19 after 100 tests with different data split: 93.85285871435981 %   
Average accuracy for K=21 after 100 tests with different data split: 93.26620809747965 %    
Average accuracy for K=23 after 100 tests with different data split: 92.58047022661833 %
Average accuracy for K=25 after 100 tests with different data split: 90.55746523509124 %

但是当我应用特征归一化时，准确率显着下降。我的kNN结果具有标准化特征：

Average accuracy for K=1 after 100 tests with different data split: 88.56128075154439 % 
Average accuracy for K=3 after 100 tests with different data split: 85.01466511662318 %    
Average accuracy for K=5 after 100 tests with different data split: 83.32096281613967 %    
Average accuracy for K=7 after 100 tests with different data split: 83.09434478900455 %   
Average accuracy for K=9 after 100 tests with different data split: 82.05628926919964 %  
Average accuracy for K=11 after 100 tests with different data split: 79.89732262550343 %   
Average accuracy for K=13 after 100 tests with different data split: 79.60617886853211 %    
Average accuracy for K=15 after 100 tests with different data split: 79.26511126374507 %    
Average accuracy for K=17 after 100 tests with different data split: 77.51457877706329 %   
Average accuracy for K=19 after 100 tests with different data split: 76.97848441605367 %    
Average accuracy for K=21 after 100 tests with different data split: 75.70005919265326 %    
Average accuracy for K=23 after 100 tests with different data split: 76.45758217099551 %   
Average accuracy for K=25 after 100 tests with different data split: 76.16619492431572 %

我在代码中的算法没有逻辑错误，我在简单数据上检查过它。

为什么 kNN 分类的准确率在特征规范化之后会降低这么多？我认为标准化本身并不会降低任何分类的准确率。那么使用特征规范化的目的是什么？

Answer 1

一般误解是规范化永远不会降低分类准确性。它很好。

如何？

连续的相对值也非常重要。事实上，它们确定了特征空间中点的位置。执行标准化时，它会严重抵消相对位置。这是感觉到的，特别是在k-NN分类中，因为它直接在点之间的距离上操作。与此相比，它在SVM中的效果并不那么强烈，因为在这种情况下，优化过程仍然可以找到一个相当准确的超平面。

您还应该注意，在这里，您使用avg（X）进行标准化。因此，考虑特定行的相邻列中的两个点。如果第一个点远低于平均值，并且第二个点远远高于其各自列的平均值，则在非标准化意义上，它们是非常接近的数值，距离计算可能会有很大差异。

永远不要指望正常化会创造奇迹。

Answer 2

KNN的工作方式是找到与之类似的实例。因为它计算两点之间的Euclidean Distance。现在通过标准化，您正在改变改变精度的特征尺度。

看看this研究。转到数字，你会发现不同的缩放技术给出了不同的精度。

特征归一化后，kNN分类的准确率下降了吗？

2 个答案: